anonymous
  • anonymous
PLEASE HELP ONE QUESTION WILL MEDAL AND FAN!
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Solve and graph the absolute value inequality: |2x + 1| ≤ 5. number line with closed dots on negative 3 and 2 with shading going in the opposite directions. number line with closed dots on negative 3 and 2 with shading in between. number line with open dots on negative 3 and 2 with shading in between. number line with closed dots on negative 2 and 2 with shading in between.
Hero
  • Hero
Hint: |ax + b| ≤ c is equivalent to -c ≤ ax + b ≤ c
anonymous
  • anonymous
What????? So confused. Could you explain better?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Hero
  • Hero
In order to properly graph the absolute value inequality, you must first solve for x. The hint I gave you shows a mathematical statement equivalent to the given statement that allows you to solve for x, which in turn, will enable you to properly graph the inequality.
anonymous
  • anonymous
ok, so |2x + 1| ≤ 5. First, would i subtract one from each side?
pooja195
  • pooja195
Set up two equations We know 2x+1≤5 and 2x+1≥−5 Solve for each \[\huge~2x+1≤5 \] \[\huge~2x+1≥−5\]
anonymous
  • anonymous
OK
anonymous
  • anonymous
2x+1<5 -1 -1 2x <4 /2 /2 x<2? for the first one?
anonymous
  • anonymous
2x+1>5 -1 -1 2x > 4 /2 /2 x>2 for the second one as well?
pooja195
  • pooja195
No.
Hero
  • Hero
It's much easier to solve it as just one compound inequality: -5 ≤ 2x + 1 ≤ 5 Subtract one from each side, then divide each side by two.
anonymous
  • anonymous
-6<2x<4?
anonymous
  • anonymous
with the line underneath the signs
Hero
  • Hero
-6 ≤ 2x ≤ 4 Then divide each side by 2.
anonymous
  • anonymous
-3
anonymous
  • anonymous
with lines underneath
Hero
  • Hero
-3 ≤ x ≤ 2
Hero
  • Hero
The inequality basically states that the solution, x, exists between -3 and 2 (inclusive)
anonymous
  • anonymous
so B?
Hero
  • Hero
Correct.
anonymous
  • anonymous
thank you so much!
Hero
  • Hero
You're welcome.

Looking for something else?

Not the answer you are looking for? Search for more explanations.