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anonymous
 one year ago
i need help with 38 anyone....i will give medals....
anonymous
 one year ago
i need help with 38 anyone....i will give medals....

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ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2In order to complete this exercise, you'll need to count the number of dots for each bin: I'll start 60  1 61  1 62  0 63  1 ... Finish the rest and we'll continue

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0601 611 620 631 640 651 660 670 683 692 702 710 721 730 741 750 763 770 781 791 804 810 824 830 841 852 863 871 881 891 905 910 924 930 940 953 960 970 981 991 1001 @ybarrap

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Concentrationalizing

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2Using your values we get (see attached):

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2You'll see how we compute mean and standard deviation in the attached above: Mean \( \bar{x}=81.72\) Standard deviation \(\sigma = 10.4\)

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2You can drill down into each cell in the spreadsheet to see the formula I used. Does this make sense?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2We used the following definition for mean and standard deviation: $$ \operatorname{E}[X] = x_1p_1 + x_2p_2 + \dotsb + x_kp_k \;\\ \operatorname{Var}(X) = \sum_{i=1}^n p_i\cdot(x_i  \mu)^2 = \sum_{i=1}^n (p_i\cdot x_i^2)  \mu^2\\ \sigma = \sqrt{Var(X)} $$ Where \(x_i\) are the bin values, 60, 61, etc...and \(p_i\) are their probabilities.

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.2And $$ \bar{x}=E[X] $$
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