A community for students.
Here's the question you clicked on:
 0 viewing
Math2400
 one year ago
Match each of the power series with its interval of convergence.
Math2400
 one year ago
Match each of the power series with its interval of convergence.

This Question is Closed

Math2400
 one year ago
Best ResponseYou've already chosen the best response.0Is this right? i only get one try so I wanted to be sure i got them ><

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ill work them myself real quick to see

Math2400
 one year ago
Best ResponseYou've already chosen the best response.0aww thanks @Concentrationalizing i can post my work if that's easier

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have better luck working it myself. Ive noticed that I can miss something a student does wrong if I just scan their work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03 and 4 need to be flipflopped

Math2400
 one year ago
Best ResponseYou've already chosen the best response.0And if i could see ur work i'd appreciate that :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Via root test on #3 \[\lim_{n \rightarrow \infty} \sqrt[n]{\left \frac{ (x9)^{n} }{ 9^{n} } \right}\] \[= \left x9 \right\cdot \lim_{n \rightarrow \infty}\frac{ 1 }{ 9 } = \frac{ 1 }{ 9 }\left x9 \right\] All the n's cancel and this is your limit. The conditions for root test are the same as for ratio test, we need to be less than 1. Thus we have: \[\frac{ 1 }{ 9 }\left x9 \right < 1 \implies \left x9 \right < 9\] which would give you the (0,18) result (since its multiple choice, I assume we dont need to actually check the endpoints)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i will not butt in and let @Concentrationalizing finish, but i am willing to bet you can guess at least two of these doing no work now i will go away

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Via ratio test on #4 \[\lim_{n \rightarrow \infty}\left \frac{ (x9)^{n+1} }{ (n+1)!9^{n+1} }\cdot \frac{ 9^{n}n! }{ (x9)^{n} } \right\] \[= \left x9 \right\lim_{n \rightarrow\infty}\left \frac{ 9^{n}n! }{ 9(n+1)9^{n}n! } \right\] \[= \left x9 \right\lim_{n \rightarrow \infty}\left \frac{ 1 }{ 9(n+1) } \right = 0\] So all values of x work since we got a result of 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I could guess them, but I'm not comfortable enough doing that yet, I'd rather just do the work and make sure I'm correct, lol @satellite73 Anyway, normally these aren't multiple choice x_x
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.