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anonymous
 one year ago
check my answer
anonymous
 one year ago
check my answer

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the slope of the line which passes through (1, 4) and (0, 1)? 3 3 4 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ y_2  y_1 }{ x_2  x_1 } = \frac{ 1  4 }{ 0  1 } = \frac{ 3 }{ 1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have mote do you mind checking?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep that's right thanks for the work!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the 2nd term when 5y^3 + 2y  3 + 6y^2  y^4 is arranged in descending order? 5y^3 < my choice 2y 6y^2 y^4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1highest to lowest degree 5 ,4,3,2,1,constant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because i rearranged it as \[y^4 + 5y^3 + 6y^2 + 2y 3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct! The first is 6y^2, second your choice!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @shinebrightlikeadimon because i rearranged it as \[y^4 + 5y^3 + 6y^2 + 2y 3\] \(\color{blue}{\text{End of Quote}}\) yep :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey, would any of you mind helping me with my problem? It's for my homework this summer, and I'm trying to finish it so I can check it with my best friend whose taking the course.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following is the conjugate of a complex number with 4 as the real part and 3 as the imaginary part? 3 + 4i 3  4i 4 + 3i 4  3i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this one idk the answer to

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.14 is the real part and 3 is imaginary so \[\huge\rm 4  3\color{red}{i}\] conjugate change the sign of imaginary part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given f(x) = (x  7)/(3), solve for f1(4). 1 19 < my choice 33 37

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x) = \frac{ x  7 }{ 3 } \] \[y = \frac{ x  7 }{ 3 }\] \[x = \frac{ y  7 }{ 3 }\] \[3x = y  7 \] \[y = 3x + 7\] \[y = 3(4) + 7 \] \[12 + 7 + 19\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Factor 4x^2  4x  24 completely. 4(x  3)(x + 2) < my choice 4(x + 3)(x  2) (4x + 3)(x  2) (4x  3)(x + 2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i used a factoring calculator b/c idk how to factor on my own

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1first of all find GCF(greatest common factor )

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right take it out 4(???????) divide all 3 terms by GCF which is 4 write your answer in the parentheses

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry forgot to write them in parenthesis

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm 4(x^2  x  6)\] now find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term B abc are Ax^2 +Bx+C

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm 4(x^2  x  6)\]\[ \huge\rm Ax^2 +Bx+C\] remember there is invisible one 1x^2 so a= what c= ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right so a times c = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes so 2 times 3 is not equal to 6 which one should be negative 3 or 2 ? remember when you add or subtract them you should get middle term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm 4(x^2  x  6)\]\[ \huge\rm Ax^2 +Bx+C\] middle term is b which is 1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1ye right so bec leading coefficient is 1 that's why just both number with (x+ first number )(x +2nd number )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thnx im going to practice it later to get better at it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the equation in pointslope form of the line passing through (3, 4) and (0, 2)? (y  8) = 2(x  3) < my choice (y + 3) = 2(x + 4) (y  2) = 2(x + 4) (y + 4) = 2(x + 3)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what is the general form of point slope ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(y  y1) = m(x  x1)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right now pick one of order pair substitute y_1 and x_1 value

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right there is a negative sign in the formula and x and y values are also negative so it becomes positive 4 and 3 that's right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay the next one idk

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simplify 2 times the 3rd root of 108 . 16 times the 3rd root of 18 8 times the 3rd root of 6 5 times the 3rd root of 4 6 times the 3rd root of 4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1factor 108 one of number must be perfect cube root

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what are factor of 108?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1start dividing 108 by 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i devide 54 by 2 too?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433717296775:dw 54 is divisible by 2 so yes divide

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433717454545:dw 27 is divisible by 3 right so divide

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433717500381:dw keep dividing ntill u get 1 or u can't divide by any number so now write factors remember exponent rule when you multiply same bases you should add their exponents \[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02 ^3 sqrt 108 = 2 ^3sqt 36

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not sure if thats correctr

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.136 is not equal to108 36 times what = 108 but 36 is not a perfect cube root it's a perfect square root

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\] do you understand this one ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433718545422:dw remember we have to factor 108 and that's what we did 2^1+2^1 = 2^{ 1+1} = 2^2 exponent when we multiply same bases we should multiply their exponents

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh i thought it was 3^2 not 3^3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\] that's how i got 2^2 and 3^3 now simplify that 2^2 =4 that stay under the 3rd root 3rd root of 3^3 = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.13 times 3 times 3 = 27 3 times 3 =9 so it's 3^3 not 3^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right 3rd can cancels with 3rd root so now you can write 3 outside the root \[2 \times 3 \sqrt[3]{2^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay i have more do you think youll be able to help?
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