anonymous
  • anonymous
check my answer
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What is the slope of the line which passes through (1, 4) and (0, 1)? 3 -3 4 -2
anonymous
  • anonymous
\[\frac{ y_2 - y_1 }{ x_2 - x_1 } = \frac{ 1 - 4 }{ 0 - 1 } = \frac{ -3 }{ -1 }\]
anonymous
  • anonymous
so 3 is my choice

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More answers

Nnesha
  • Nnesha
yep
anonymous
  • anonymous
Correct!
anonymous
  • anonymous
i have mote do you mind checking?
Nnesha
  • Nnesha
sure
anonymous
  • anonymous
NOT AT ALL!
anonymous
  • anonymous
whoops caps
Nnesha
  • Nnesha
yep that's right thanks for the work!
anonymous
  • anonymous
What is the 2nd term when 5y^3 + 2y - 3 + 6y^2 - y^4 is arranged in descending order? 5y^3 <--- my choice 2y 6y^2 -y^4
Nnesha
  • Nnesha
highest to lowest degree 5 ,4,3,2,1,constant
anonymous
  • anonymous
because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\]
anonymous
  • anonymous
Correct! The first is 6y^2, second your choice!
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @shinebrightlikeadimon because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\] \(\color{blue}{\text{End of Quote}}\) yep :-)
anonymous
  • anonymous
i meant +5y^3
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
Hey, would any of you mind helping me with my problem? It's for my homework this summer, and I'm trying to finish it so I can check it with my best friend whose taking the course.
anonymous
  • anonymous
Which of the following is the conjugate of a complex number with 4 as the real part and -3 as the imaginary part? -3 + 4i 3 - 4i 4 + 3i 4 - 3i
anonymous
  • anonymous
this one idk the answer to
Nnesha
  • Nnesha
4 is the real part and -3 is imaginary so \[\huge\rm 4 - 3\color{red}{i}\] conjugate change the sign of imaginary part
anonymous
  • anonymous
oh okay thnx
anonymous
  • anonymous
Given f(x) = (x - 7)/(3), solve for f-1(4). -1 19 <--- my choice 33 37
anonymous
  • anonymous
\[f(x) = \frac{ x - 7 }{ 3 } \] \[y = \frac{ x - 7 }{ 3 }\] \[x = \frac{ y - 7 }{ 3 }\] \[3x = y - 7 \] \[y = 3x + 7\] \[y = 3(4) + 7 \] \[12 + 7 + 19\]
Nnesha
  • Nnesha
yep right
anonymous
  • anonymous
yay
anonymous
  • anonymous
Factor 4x^2 - 4x - 24 completely. 4(x - 3)(x + 2) <--- my choice 4(x + 3)(x - 2) (4x + 3)(x - 2) (4x - 3)(x + 2)
anonymous
  • anonymous
i used a factoring calculator b/c idk how to factor on my own
Nnesha
  • Nnesha
first of all find GCF(greatest common factor )
anonymous
  • anonymous
4
Nnesha
  • Nnesha
yes right take it out 4(???????) divide all 3 terms by GCF which is 4 write your answer in the parentheses
anonymous
  • anonymous
x^2 - x - 6
anonymous
  • anonymous
sorry forgot to write them in parenthesis
Nnesha
  • Nnesha
\[\huge\rm 4(x^2 - x - 6)\] now find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term B abc are Ax^2 +Bx+C
anonymous
  • anonymous
idk 2 and 3
Nnesha
  • Nnesha
\[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\] remember there is invisible one 1x^2 so a= what c= ?
anonymous
  • anonymous
a = 1 and c = -6
Nnesha
  • Nnesha
yes right so a times c = ?
anonymous
  • anonymous
-6
Nnesha
  • Nnesha
yes so 2 times 3 is not equal to -6 which one should be negative 3 or 2 ? remember when you add or subtract them you should get middle term
Nnesha
  • Nnesha
\[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\] middle term is b which is -1
anonymous
  • anonymous
-3
Nnesha
  • Nnesha
ye right so bec leading coefficient is 1 that's why just both number with (x+ first number )(x +2nd number )
Nnesha
  • Nnesha
done!
anonymous
  • anonymous
thnx im going to practice it later to get better at it
Nnesha
  • Nnesha
great! gO_od luck!
anonymous
  • anonymous
thnx
anonymous
  • anonymous
What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)? (y - 8) = 2(x - 3) <-- my choice (y + 3) = -2(x + 4) (y - 2) = -2(x + 4) (y + 4) = 2(x + 3)
Nnesha
  • Nnesha
what is the general form of point slope ?
Nnesha
  • Nnesha
equation *
anonymous
  • anonymous
(y - y1) = m(x - x1)
Nnesha
  • Nnesha
yes right now pick one of order pair substitute y_1 and x_1 value
anonymous
  • anonymous
y + 4 = m(x +3)
Nnesha
  • Nnesha
yes right there is a negative sign in the formula and x and y values are also negative so it becomes positive 4 and 3 that's right
anonymous
  • anonymous
oh so D
Nnesha
  • Nnesha
yes
anonymous
  • anonymous
okay the next one idk
anonymous
  • anonymous
Simplify 2 times the 3rd root of 108 . 16 times the 3rd root of 18 8 times the 3rd root of 6 5 times the 3rd root of 4 6 times the 3rd root of 4
Nnesha
  • Nnesha
factor 108 one of number must be perfect cube root
anonymous
  • anonymous
what
Nnesha
  • Nnesha
what are factor of 108?
anonymous
  • anonymous
idk
Nnesha
  • Nnesha
start dividing 108 by 2
anonymous
  • anonymous
54,
anonymous
  • anonymous
do i devide 54 by 2 too?
Nnesha
  • Nnesha
yes right
Nnesha
  • Nnesha
|dw:1433717296775:dw| 54 is divisible by 2 so yes divide
anonymous
  • anonymous
27
Nnesha
  • Nnesha
|dw:1433717454545:dw| 27 is divisible by 3 right so divide
anonymous
  • anonymous
8
anonymous
  • anonymous
i mean 9
Nnesha
  • Nnesha
|dw:1433717500381:dw| keep dividing ntill u get 1 or u can't divide by any number so now write factors remember exponent rule when you multiply same bases you should add their exponents \[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\]
Nnesha
  • Nnesha
now simplify that
anonymous
  • anonymous
2 ^3 sqrt 108 = 2 ^3sqt 36
anonymous
  • anonymous
not sure if thats correctr
Nnesha
  • Nnesha
36 is not equal to108 36 times what = 108 but 36 is not a perfect cube root it's a perfect square root
Nnesha
  • Nnesha
\[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\] do you understand this one ?
anonymous
  • anonymous
no
Nnesha
  • Nnesha
|dw:1433718545422:dw| remember we have to factor 108 and that's what we did 2^1+2^1 = 2^{ 1+1} = 2^2 exponent when we multiply same bases we should multiply their exponents
anonymous
  • anonymous
oh i thought it was 3^2 not 3^3
Nnesha
  • Nnesha
\[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\] that's how i got 2^2 and 3^3 now simplify that 2^2 =4 that stay under the 3rd root 3rd root of 3^3 = ?
anonymous
  • anonymous
its 3
Nnesha
  • Nnesha
3 times 3 times 3 = 27 3 times 3 =9 so it's 3^3 not 3^2
Nnesha
  • Nnesha
yes right 3rd can cancels with 3rd root so now you can write 3 outside the root \[2 \times 3 \sqrt[3]{2^2}\]
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
so its D
Nnesha
  • Nnesha
ye
anonymous
  • anonymous
yay i have more do you think youll be able to help?

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