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anonymous

  • one year ago

check my answer

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  1. anonymous
    • one year ago
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    What is the slope of the line which passes through (1, 4) and (0, 1)? 3 -3 4 -2

  2. anonymous
    • one year ago
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    \[\frac{ y_2 - y_1 }{ x_2 - x_1 } = \frac{ 1 - 4 }{ 0 - 1 } = \frac{ -3 }{ -1 }\]

  3. anonymous
    • one year ago
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    so 3 is my choice

  4. Nnesha
    • one year ago
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    yep

  5. anonymous
    • one year ago
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    Correct!

  6. anonymous
    • one year ago
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    i have mote do you mind checking?

  7. Nnesha
    • one year ago
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    sure

  8. anonymous
    • one year ago
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    NOT AT ALL!

  9. anonymous
    • one year ago
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    whoops caps

  10. Nnesha
    • one year ago
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    yep that's right thanks for the work!

  11. anonymous
    • one year ago
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    What is the 2nd term when 5y^3 + 2y - 3 + 6y^2 - y^4 is arranged in descending order? 5y^3 <--- my choice 2y 6y^2 -y^4

  12. Nnesha
    • one year ago
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    highest to lowest degree 5 ,4,3,2,1,constant

  13. anonymous
    • one year ago
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    because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\]

  14. anonymous
    • one year ago
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    Correct! The first is 6y^2, second your choice!

  15. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @shinebrightlikeadimon because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\] \(\color{blue}{\text{End of Quote}}\) yep :-)

  16. anonymous
    • one year ago
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    i meant +5y^3

  17. anonymous
    • one year ago
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    okay thanks

  18. anonymous
    • one year ago
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    Hey, would any of you mind helping me with my problem? It's for my homework this summer, and I'm trying to finish it so I can check it with my best friend whose taking the course.

  19. anonymous
    • one year ago
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    Which of the following is the conjugate of a complex number with 4 as the real part and -3 as the imaginary part? -3 + 4i 3 - 4i 4 + 3i 4 - 3i

  20. anonymous
    • one year ago
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    this one idk the answer to

  21. Nnesha
    • one year ago
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    4 is the real part and -3 is imaginary so \[\huge\rm 4 - 3\color{red}{i}\] conjugate change the sign of imaginary part

  22. anonymous
    • one year ago
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    oh okay thnx

  23. anonymous
    • one year ago
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    Given f(x) = (x - 7)/(3), solve for f-1(4). -1 19 <--- my choice 33 37

  24. anonymous
    • one year ago
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    \[f(x) = \frac{ x - 7 }{ 3 } \] \[y = \frac{ x - 7 }{ 3 }\] \[x = \frac{ y - 7 }{ 3 }\] \[3x = y - 7 \] \[y = 3x + 7\] \[y = 3(4) + 7 \] \[12 + 7 + 19\]

  25. Nnesha
    • one year ago
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    yep right

  26. anonymous
    • one year ago
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    yay

  27. anonymous
    • one year ago
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    Factor 4x^2 - 4x - 24 completely. 4(x - 3)(x + 2) <--- my choice 4(x + 3)(x - 2) (4x + 3)(x - 2) (4x - 3)(x + 2)

  28. anonymous
    • one year ago
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    i used a factoring calculator b/c idk how to factor on my own

  29. Nnesha
    • one year ago
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    first of all find GCF(greatest common factor )

  30. anonymous
    • one year ago
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    4

  31. Nnesha
    • one year ago
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    yes right take it out 4(???????) divide all 3 terms by GCF which is 4 write your answer in the parentheses

  32. anonymous
    • one year ago
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    x^2 - x - 6

  33. anonymous
    • one year ago
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    sorry forgot to write them in parenthesis

  34. Nnesha
    • one year ago
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    \[\huge\rm 4(x^2 - x - 6)\] now find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term B abc are Ax^2 +Bx+C

  35. anonymous
    • one year ago
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    idk 2 and 3

  36. Nnesha
    • one year ago
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    \[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\] remember there is invisible one 1x^2 so a= what c= ?

  37. anonymous
    • one year ago
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    a = 1 and c = -6

  38. Nnesha
    • one year ago
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    yes right so a times c = ?

  39. anonymous
    • one year ago
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    -6

  40. Nnesha
    • one year ago
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    yes so 2 times 3 is not equal to -6 which one should be negative 3 or 2 ? remember when you add or subtract them you should get middle term

  41. Nnesha
    • one year ago
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    \[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\] middle term is b which is -1

  42. anonymous
    • one year ago
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    -3

  43. Nnesha
    • one year ago
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    ye right so bec leading coefficient is 1 that's why just both number with (x+ first number )(x +2nd number )

  44. Nnesha
    • one year ago
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    done!

  45. anonymous
    • one year ago
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    thnx im going to practice it later to get better at it

  46. Nnesha
    • one year ago
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    great! gO_od luck!

  47. anonymous
    • one year ago
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    thnx

  48. anonymous
    • one year ago
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    What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)? (y - 8) = 2(x - 3) <-- my choice (y + 3) = -2(x + 4) (y - 2) = -2(x + 4) (y + 4) = 2(x + 3)

  49. Nnesha
    • one year ago
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    what is the general form of point slope ?

  50. Nnesha
    • one year ago
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    equation *

  51. anonymous
    • one year ago
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    (y - y1) = m(x - x1)

  52. Nnesha
    • one year ago
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    yes right now pick one of order pair substitute y_1 and x_1 value

  53. anonymous
    • one year ago
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    y + 4 = m(x +3)

  54. Nnesha
    • one year ago
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    yes right there is a negative sign in the formula and x and y values are also negative so it becomes positive 4 and 3 that's right

  55. anonymous
    • one year ago
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    oh so D

  56. Nnesha
    • one year ago
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    yes

  57. anonymous
    • one year ago
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    okay the next one idk

  58. anonymous
    • one year ago
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    Simplify 2 times the 3rd root of 108 . 16 times the 3rd root of 18 8 times the 3rd root of 6 5 times the 3rd root of 4 6 times the 3rd root of 4

  59. Nnesha
    • one year ago
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    factor 108 one of number must be perfect cube root

  60. anonymous
    • one year ago
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    what

  61. Nnesha
    • one year ago
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    what are factor of 108?

  62. anonymous
    • one year ago
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    idk

  63. Nnesha
    • one year ago
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    start dividing 108 by 2

  64. anonymous
    • one year ago
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    54,

  65. anonymous
    • one year ago
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    do i devide 54 by 2 too?

  66. Nnesha
    • one year ago
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    yes right

  67. Nnesha
    • one year ago
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    |dw:1433717296775:dw| 54 is divisible by 2 so yes divide

  68. anonymous
    • one year ago
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    27

  69. Nnesha
    • one year ago
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    |dw:1433717454545:dw| 27 is divisible by 3 right so divide

  70. anonymous
    • one year ago
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    8

  71. anonymous
    • one year ago
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    i mean 9

  72. Nnesha
    • one year ago
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    |dw:1433717500381:dw| keep dividing ntill u get 1 or u can't divide by any number so now write factors remember exponent rule when you multiply same bases you should add their exponents \[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\]

  73. Nnesha
    • one year ago
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    now simplify that

  74. anonymous
    • one year ago
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    2 ^3 sqrt 108 = 2 ^3sqt 36

  75. anonymous
    • one year ago
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    not sure if thats correctr

  76. Nnesha
    • one year ago
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    36 is not equal to108 36 times what = 108 but 36 is not a perfect cube root it's a perfect square root

  77. Nnesha
    • one year ago
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    \[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\] do you understand this one ?

  78. anonymous
    • one year ago
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    no

  79. Nnesha
    • one year ago
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    |dw:1433718545422:dw| remember we have to factor 108 and that's what we did 2^1+2^1 = 2^{ 1+1} = 2^2 exponent when we multiply same bases we should multiply their exponents

  80. anonymous
    • one year ago
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    oh i thought it was 3^2 not 3^3

  81. Nnesha
    • one year ago
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    \[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\] that's how i got 2^2 and 3^3 now simplify that 2^2 =4 that stay under the 3rd root 3rd root of 3^3 = ?

  82. anonymous
    • one year ago
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    its 3

  83. Nnesha
    • one year ago
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    3 times 3 times 3 = 27 3 times 3 =9 so it's 3^3 not 3^2

  84. Nnesha
    • one year ago
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    yes right 3rd can cancels with 3rd root so now you can write 3 outside the root \[2 \times 3 \sqrt[3]{2^2}\]

  85. anonymous
    • one year ago
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    oh ok

  86. anonymous
    • one year ago
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    so its D

  87. Nnesha
    • one year ago
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    ye

  88. anonymous
    • one year ago
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    yay i have more do you think youll be able to help?

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