check my answer

- anonymous

check my answer

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

What is the slope of the line which passes through (1, 4) and (0, 1)?
3
-3
4
-2

- anonymous

\[\frac{ y_2 - y_1 }{ x_2 - x_1 } = \frac{ 1 - 4 }{ 0 - 1 } = \frac{ -3 }{ -1 }\]

- anonymous

so 3 is my choice

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- Nnesha

yep

- anonymous

Correct!

- anonymous

i have mote do you mind checking?

- Nnesha

sure

- anonymous

NOT AT ALL!

- anonymous

whoops caps

- Nnesha

yep that's right thanks for the work!

- anonymous

What is the 2nd term when 5y^3 + 2y - 3 + 6y^2 - y^4 is arranged in descending order?
5y^3 <--- my choice
2y
6y^2
-y^4

- Nnesha

highest to lowest degree
5 ,4,3,2,1,constant

- anonymous

because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\]

- anonymous

Correct! The first is 6y^2, second your choice!

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @shinebrightlikeadimon
because i rearranged it as \[-y^4 + 5y^3 + 6y^2 + 2y -3\]
\(\color{blue}{\text{End of Quote}}\)
yep :-)

- anonymous

i meant +5y^3

- anonymous

okay thanks

- anonymous

Hey, would any of you mind helping me with my problem? It's for my homework this summer, and I'm trying to finish it so I can check it with my best friend whose taking the course.

- anonymous

Which of the following is the conjugate of a complex number with 4 as the real part and -3 as the imaginary part?
-3 + 4i
3 - 4i
4 + 3i
4 - 3i

- anonymous

this one idk the answer to

- Nnesha

4 is the real part
and -3 is imaginary
so \[\huge\rm 4 - 3\color{red}{i}\]
conjugate change the sign of imaginary part

- anonymous

oh okay thnx

- anonymous

Given f(x) = (x - 7)/(3), solve for f-1(4).
-1
19 <--- my choice
33
37

- anonymous

\[f(x) = \frac{ x - 7 }{ 3 } \]
\[y = \frac{ x - 7 }{ 3 }\]
\[x = \frac{ y - 7 }{ 3 }\]
\[3x = y - 7 \]
\[y = 3x + 7\]
\[y = 3(4) + 7 \] \[12 + 7 + 19\]

- Nnesha

yep right

- anonymous

yay

- anonymous

Factor 4x^2 - 4x - 24 completely.
4(x - 3)(x + 2) <--- my choice
4(x + 3)(x - 2)
(4x + 3)(x - 2)
(4x - 3)(x + 2)

- anonymous

i used a factoring calculator b/c idk how to factor on my own

- Nnesha

first of all find GCF(greatest common factor )

- anonymous

4

- Nnesha

yes right take it out
4(???????)
divide all 3 terms by GCF which is 4 write your answer in the parentheses

- anonymous

x^2 - x - 6

- anonymous

sorry forgot to write them in parenthesis

- Nnesha

\[\huge\rm 4(x^2 - x - 6)\]
now find two number if you multiply them you should get product of AC
and if you add or subtract them you should get middle term B
abc are Ax^2 +Bx+C

- anonymous

idk 2 and 3

- Nnesha

\[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\]
remember there is invisible one 1x^2
so
a= what
c= ?

- anonymous

a = 1 and c = -6

- Nnesha

yes right
so a times c = ?

- anonymous

-6

- Nnesha

yes so 2 times 3 is not equal to -6
which one should be negative 3 or 2 ?
remember when you add or subtract them you should get middle term

- Nnesha

\[\huge\rm 4(x^2 - x - 6)\]\[ \huge\rm Ax^2 +Bx+C\]
middle term is b which is -1

- anonymous

-3

- Nnesha

ye right so bec leading coefficient is 1 that's why just both number with
(x+ first number )(x +2nd number )

- Nnesha

done!

- anonymous

thnx im going to practice it later to get better at it

- Nnesha

great!
gO_od luck!

- anonymous

thnx

- anonymous

What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)?
(y - 8) = 2(x - 3) <-- my choice
(y + 3) = -2(x + 4)
(y - 2) = -2(x + 4)
(y + 4) = 2(x + 3)

- Nnesha

what is the general form of point slope ?

- Nnesha

equation *

- anonymous

(y - y1) = m(x - x1)

- Nnesha

yes right now pick one of order pair substitute y_1 and x_1 value

- anonymous

y + 4 = m(x +3)

- Nnesha

yes right there is a negative sign in the formula and x and y values are also negative so it becomes positive 4 and 3 that's right

- anonymous

oh so D

- Nnesha

yes

- anonymous

okay the next one idk

- anonymous

Simplify 2 times the 3rd root of 108 .
16 times the 3rd root of 18
8 times the 3rd root of 6
5 times the 3rd root of 4
6 times the 3rd root of 4

- Nnesha

factor 108 one of number must be perfect cube root

- anonymous

what

- Nnesha

what are factor of 108?

- anonymous

idk

- Nnesha

start dividing 108 by 2

- anonymous

54,

- anonymous

do i devide 54 by 2 too?

- Nnesha

yes right

- Nnesha

|dw:1433717296775:dw|
54 is divisible by 2 so yes divide

- anonymous

27

- Nnesha

|dw:1433717454545:dw|
27 is divisible by 3 right so divide

- anonymous

8

- anonymous

i mean 9

- Nnesha

|dw:1433717500381:dw|
keep dividing ntill u get 1 or u can't divide by any number
so now write factors
remember exponent rule when you multiply same bases you should add their exponents \[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\]

- Nnesha

now simplify that

- anonymous

2 ^3 sqrt 108 = 2 ^3sqt 36

- anonymous

not sure if thats correctr

- Nnesha

36 is not equal to108
36 times what = 108
but 36 is not a perfect cube root
it's a perfect square root

- Nnesha

\[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\]
do you understand this one ?

- anonymous

no

- Nnesha

|dw:1433718545422:dw|
remember we have to factor 108 and that's what we did
2^1+2^1 = 2^{ 1+1} = 2^2
exponent when we multiply same bases we should multiply their exponents

- anonymous

oh i thought it was 3^2 not 3^3

- Nnesha

\[2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}\]
that's how i got 2^2 and 3^3
now simplify that
2^2 =4 that stay under the 3rd root
3rd root of 3^3 = ?

- anonymous

its 3

- Nnesha

3 times 3 times 3 = 27
3 times 3 =9 so it's 3^3 not 3^2

- Nnesha

yes right 3rd can cancels with 3rd root so now you can write 3 outside the root \[2 \times 3 \sqrt[3]{2^2}\]

- anonymous

oh ok

- anonymous

so its D

- Nnesha

ye

- anonymous

yay i have more do you think youll be able to help?

Looking for something else?

Not the answer you are looking for? Search for more explanations.