## anonymous one year ago check my answer

1. anonymous

What is the slope of the line which passes through (1, 4) and (0, 1)? 3 -3 4 -2

2. anonymous

$\frac{ y_2 - y_1 }{ x_2 - x_1 } = \frac{ 1 - 4 }{ 0 - 1 } = \frac{ -3 }{ -1 }$

3. anonymous

so 3 is my choice

4. Nnesha

yep

5. anonymous

Correct!

6. anonymous

i have mote do you mind checking?

7. Nnesha

sure

8. anonymous

NOT AT ALL!

9. anonymous

whoops caps

10. Nnesha

yep that's right thanks for the work!

11. anonymous

What is the 2nd term when 5y^3 + 2y - 3 + 6y^2 - y^4 is arranged in descending order? 5y^3 <--- my choice 2y 6y^2 -y^4

12. Nnesha

highest to lowest degree 5 ,4,3,2,1,constant

13. anonymous

because i rearranged it as $-y^4 + 5y^3 + 6y^2 + 2y -3$

14. anonymous

Correct! The first is 6y^2, second your choice!

15. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @shinebrightlikeadimon because i rearranged it as $-y^4 + 5y^3 + 6y^2 + 2y -3$ $$\color{blue}{\text{End of Quote}}$$ yep :-)

16. anonymous

i meant +5y^3

17. anonymous

okay thanks

18. anonymous

Hey, would any of you mind helping me with my problem? It's for my homework this summer, and I'm trying to finish it so I can check it with my best friend whose taking the course.

19. anonymous

Which of the following is the conjugate of a complex number with 4 as the real part and -3 as the imaginary part? -3 + 4i 3 - 4i 4 + 3i 4 - 3i

20. anonymous

this one idk the answer to

21. Nnesha

4 is the real part and -3 is imaginary so $\huge\rm 4 - 3\color{red}{i}$ conjugate change the sign of imaginary part

22. anonymous

oh okay thnx

23. anonymous

Given f(x) = (x - 7)/(3), solve for f-1(4). -1 19 <--- my choice 33 37

24. anonymous

$f(x) = \frac{ x - 7 }{ 3 }$ $y = \frac{ x - 7 }{ 3 }$ $x = \frac{ y - 7 }{ 3 }$ $3x = y - 7$ $y = 3x + 7$ $y = 3(4) + 7$ $12 + 7 + 19$

25. Nnesha

yep right

26. anonymous

yay

27. anonymous

Factor 4x^2 - 4x - 24 completely. 4(x - 3)(x + 2) <--- my choice 4(x + 3)(x - 2) (4x + 3)(x - 2) (4x - 3)(x + 2)

28. anonymous

i used a factoring calculator b/c idk how to factor on my own

29. Nnesha

first of all find GCF(greatest common factor )

30. anonymous

4

31. Nnesha

yes right take it out 4(???????) divide all 3 terms by GCF which is 4 write your answer in the parentheses

32. anonymous

x^2 - x - 6

33. anonymous

sorry forgot to write them in parenthesis

34. Nnesha

$\huge\rm 4(x^2 - x - 6)$ now find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term B abc are Ax^2 +Bx+C

35. anonymous

idk 2 and 3

36. Nnesha

$\huge\rm 4(x^2 - x - 6)$$\huge\rm Ax^2 +Bx+C$ remember there is invisible one 1x^2 so a= what c= ?

37. anonymous

a = 1 and c = -6

38. Nnesha

yes right so a times c = ?

39. anonymous

-6

40. Nnesha

yes so 2 times 3 is not equal to -6 which one should be negative 3 or 2 ? remember when you add or subtract them you should get middle term

41. Nnesha

$\huge\rm 4(x^2 - x - 6)$$\huge\rm Ax^2 +Bx+C$ middle term is b which is -1

42. anonymous

-3

43. Nnesha

ye right so bec leading coefficient is 1 that's why just both number with (x+ first number )(x +2nd number )

44. Nnesha

done!

45. anonymous

thnx im going to practice it later to get better at it

46. Nnesha

great! gO_od luck!

47. anonymous

thnx

48. anonymous

What is the equation in point-slope form of the line passing through (-3, -4) and (0, 2)? (y - 8) = 2(x - 3) <-- my choice (y + 3) = -2(x + 4) (y - 2) = -2(x + 4) (y + 4) = 2(x + 3)

49. Nnesha

what is the general form of point slope ?

50. Nnesha

equation *

51. anonymous

(y - y1) = m(x - x1)

52. Nnesha

yes right now pick one of order pair substitute y_1 and x_1 value

53. anonymous

y + 4 = m(x +3)

54. Nnesha

yes right there is a negative sign in the formula and x and y values are also negative so it becomes positive 4 and 3 that's right

55. anonymous

oh so D

56. Nnesha

yes

57. anonymous

okay the next one idk

58. anonymous

Simplify 2 times the 3rd root of 108 . 16 times the 3rd root of 18 8 times the 3rd root of 6 5 times the 3rd root of 4 6 times the 3rd root of 4

59. Nnesha

factor 108 one of number must be perfect cube root

60. anonymous

what

61. Nnesha

what are factor of 108?

62. anonymous

idk

63. Nnesha

start dividing 108 by 2

64. anonymous

54,

65. anonymous

do i devide 54 by 2 too?

66. Nnesha

yes right

67. Nnesha

|dw:1433717296775:dw| 54 is divisible by 2 so yes divide

68. anonymous

27

69. Nnesha

|dw:1433717454545:dw| 27 is divisible by 3 right so divide

70. anonymous

8

71. anonymous

i mean 9

72. Nnesha

|dw:1433717500381:dw| keep dividing ntill u get 1 or u can't divide by any number so now write factors remember exponent rule when you multiply same bases you should add their exponents $2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}$

73. Nnesha

now simplify that

74. anonymous

2 ^3 sqrt 108 = 2 ^3sqt 36

75. anonymous

not sure if thats correctr

76. Nnesha

36 is not equal to108 36 times what = 108 but 36 is not a perfect cube root it's a perfect square root

77. Nnesha

$2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}$ do you understand this one ?

78. anonymous

no

79. Nnesha

|dw:1433718545422:dw| remember we have to factor 108 and that's what we did 2^1+2^1 = 2^{ 1+1} = 2^2 exponent when we multiply same bases we should multiply their exponents

80. anonymous

oh i thought it was 3^2 not 3^3

81. Nnesha

$2\sqrt[3]{2 \times 2 \times 3 \times 3 \times 3 } =2 \sqrt[3]{2^2 \times 3^3}$ that's how i got 2^2 and 3^3 now simplify that 2^2 =4 that stay under the 3rd root 3rd root of 3^3 = ?

82. anonymous

its 3

83. Nnesha

3 times 3 times 3 = 27 3 times 3 =9 so it's 3^3 not 3^2

84. Nnesha

yes right 3rd can cancels with 3rd root so now you can write 3 outside the root $2 \times 3 \sqrt[3]{2^2}$

85. anonymous

oh ok

86. anonymous

so its D

87. Nnesha

ye

88. anonymous

yay i have more do you think youll be able to help?