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|dw:1433715559882:dw|

i've simplified it to 2x-y+z=0
how do i make that into an eigenvector?

I'm having trouble seeing how got an egivenvalue of 3

Okay, so let's check and see if 3 works then

the original matrix was |dw:1433716009320:dw|

I found that one eigenvalue was 3 and the other two were complex numbers

I'm just trying to find the eigenvector for 3 right now

I plugged 3 into the matrix to get the matrix that i originally posted

I just realized the other two eigenvalues aren't complex btw

for this other matrix you have I see how you got 3 now

for the first matrix all the egienvalues were 0

sorry i wasn't clear. The first matrix is the second matrix with the eigenvalue 3 plugged in

|dw:1433716555159:dw|

which produced

|dw:1433716643997:dw|

after i simplified it a bit

oops forgot to put my one column vector in

after simplifying i got
2x-y+z=0

the second and third row should cancel

err 2x-y+z=0

that 2 should be 3

so can i use ( 1 , 1 , -1) as the eigenvector?

as one egienvector

3 is repeated twice

ok so we have to find a second egienvector

for lambda=3

we can use the (1,1,-1) as the first

ok I get it now, thanks a lot!

notice I replace that zero vector with the other egienvector we found for lambda=3

Thanks for the help!

sorry the first link might not work

Was 3 a repeated eigenvalue?

yah yah!

I think he is going to need that other egienvector