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anonymous
 one year ago
In an industrial process, the temperature of a fixed amount of gas in a rigid container drops from 50 degrees Celsius to 25 degrees Celsius. What will be the final pressure in the container if the initial pressure is 3.8 atmospheres?
1.9 atm
3.5 atm
4.1 atm
7.6 atm
anonymous
 one year ago
In an industrial process, the temperature of a fixed amount of gas in a rigid container drops from 50 degrees Celsius to 25 degrees Celsius. What will be the final pressure in the container if the initial pressure is 3.8 atmospheres? 1.9 atm 3.5 atm 4.1 atm 7.6 atm

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aaronq
 one year ago
Best ResponseYou've already chosen the best response.1So for this question you would use: \(\sf \large \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\) the temperature needs to be in kelvin though, so add 273 to the temps in celsius.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea what you mean @aaronq

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1Do you know what the question is asking?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1lol have you read it? do you know anything from this class..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea lol I just have a couple questions.

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1So make an effort and show that you're trying. You need to follow the formula I posted earlier. It compares a closed system, at two instances, when the temp is 50 and 25 celsius.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.050 is 323.15 and 25 is 298.15

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1great. we're also told that the initial pressure is 3.8 atm. At what temp ( 25 or 50) i this true?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1In other words, what's the initial temperature?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I divide 50/3.8 or 323.15/3.8

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1lets use some algebra to rearrange the whole equation first. \(\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\rightarrow \sf \dfrac{3.8~atm}{323.15~K}=\dfrac{P_2}{298.15~K}\) \(\sf P_2=\dfrac{3.8~atm*298.15~\cancel K}{323.15~\cancel K}\)

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1now just carryout the operations and you should have the answer
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