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anonymous

  • one year ago

in an organic synthesis 62% yield of product is achieved. which of these conversions are consistent with this information 1) 74 g of butan-2-ol -> 44.64 g of butanone 2)74 g of butan-1-ol -> 54.56 g of butanoic acid 3) 74 g of 2-methylpropane-1-ol -> 54.56 g of 2-methylpropanoic acid

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  1. aaronq
    • one year ago
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    You have to try all of them individually, use the equation at the bottom. Assuming that the coefficients for the reactants and products involved are 1... \(\sf moles_R=moles_P\) sub in: \(\sf moles_R=\dfrac{mass_R}{Molar~mass_R}\) \(\sf \dfrac{mass_R}{Molar~mass_R}=\dfrac{mass_P}{Molar~mass_P}\) therefore: \(\sf mass_P= \dfrac{mass_R*Molar~mass_P}{Molar~mass_R}\) this is the theoretical yield, since only 60% was made, multiply by 0.6. So, \(\sf \large mass_P= 0.6*\dfrac{mass_R*Molar~mass_P}{Molar~mass_R}\)

  2. anonymous
    • one year ago
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    For one i tried (74×72)/74 and then multiplied by 0.6 it gives 43.2. Where am i wrong?

  3. aaronq
    • one year ago
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    hm idk, i tried them too didn't get any of the possible answers

  4. anonymous
    • one year ago
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    And tomorrow's my exam :(

  5. anonymous
    • one year ago
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    Ohhhh i'm so sorry it's not 60% it's 62% my apologies

  6. aaronq
    • one year ago
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    ohh lol no worries it should be the first or the second then

  7. anonymous
    • one year ago
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    It's just i copied it from internet

  8. anonymous
    • one year ago
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    All three of them are correct according to marking scheme

  9. aaronq
    • one year ago
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    oh okay. double check them i suppose

  10. anonymous
    • one year ago
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    There must be a typo or something :/

  11. anonymous
    • one year ago
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    First two are correct the last one is creating problem now.

  12. aaronq
    • one year ago
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    i get 54.53828 for the last one

  13. anonymous
    • one year ago
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    No i got it correct yaaayyy

  14. anonymous
    • one year ago
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    It was (0.62×74×88)÷74

  15. aaronq
    • one year ago
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    awesome!

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