anonymous
  • anonymous
in an organic synthesis 62% yield of product is achieved. which of these conversions are consistent with this information 1) 74 g of butan-2-ol -> 44.64 g of butanone 2)74 g of butan-1-ol -> 54.56 g of butanoic acid 3) 74 g of 2-methylpropane-1-ol -> 54.56 g of 2-methylpropanoic acid
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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aaronq
  • aaronq
You have to try all of them individually, use the equation at the bottom. Assuming that the coefficients for the reactants and products involved are 1... \(\sf moles_R=moles_P\) sub in: \(\sf moles_R=\dfrac{mass_R}{Molar~mass_R}\) \(\sf \dfrac{mass_R}{Molar~mass_R}=\dfrac{mass_P}{Molar~mass_P}\) therefore: \(\sf mass_P= \dfrac{mass_R*Molar~mass_P}{Molar~mass_R}\) this is the theoretical yield, since only 60% was made, multiply by 0.6. So, \(\sf \large mass_P= 0.6*\dfrac{mass_R*Molar~mass_P}{Molar~mass_R}\)
anonymous
  • anonymous
For one i tried (74×72)/74 and then multiplied by 0.6 it gives 43.2. Where am i wrong?
aaronq
  • aaronq
hm idk, i tried them too didn't get any of the possible answers

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anonymous
  • anonymous
And tomorrow's my exam :(
anonymous
  • anonymous
Ohhhh i'm so sorry it's not 60% it's 62% my apologies
aaronq
  • aaronq
ohh lol no worries it should be the first or the second then
anonymous
  • anonymous
It's just i copied it from internet
anonymous
  • anonymous
All three of them are correct according to marking scheme
aaronq
  • aaronq
oh okay. double check them i suppose
anonymous
  • anonymous
There must be a typo or something :/
anonymous
  • anonymous
First two are correct the last one is creating problem now.
aaronq
  • aaronq
i get 54.53828 for the last one
anonymous
  • anonymous
No i got it correct yaaayyy
anonymous
  • anonymous
It was (0.62×74×88)÷74
aaronq
  • aaronq
awesome!

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