anonymous
  • anonymous
help @Nnesha
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
What is the simplified form of 15 times x to the sixth power over 20 times y to the fifth power times the fraction 6 times y-squared over 5 times x to the fourth power ? 9 x-squared over 10 y-cubed 9 x cubed over 10 y-squared 10 x cubed over 9 y-squared 10 x squared over 9 y-cubed
campbell_st
  • campbell_st
so the question is \[\frac{15x^6}{20y^5} \times \frac{6y^2}{5x^4}\] so if you simplify it you get \[\frac{90x^6y^2}{100x^4y^5}\] start by simplfying 90/100 = then with the powers, use the index law for division, subtract the powers for the same base \[\frac{x^a}{x^b} = x^{a - b}\] if you get a negative power it just indicates a fraction \[x^{-a} = \frac{1}{x^a}\] hope it helps
anonymous
  • anonymous
@Nnesha can you help i dont get ot

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Nnesha
  • Nnesha
everything is there! :-) reread that
anonymous
  • anonymous
i dont understand it
Nnesha
  • Nnesha
tell me what part u don't get 4rm that ? i have nothing to add :-)
Nnesha
  • Nnesha
divide 90/100= ?? keep it in fraction form reduce the fraction
Nnesha
  • Nnesha
if there are same bases at the denominator and numerator you have to use exponent rule \[\huge\rm \frac{ x^a }{ x^b } = x^{a-b}\]
Nnesha
  • Nnesha
for example \[\rm \frac{ 3^3 }{ 3^2 } = 3^{3-2}\]
anonymous
  • anonymous
okay so i got 9x^3/10y^3
anonymous
  • anonymous
like when i used a calculator idk this one is confusing
Nnesha
  • Nnesha
in other words x^6 can be written as \[\huge\rm \frac{ x \times x \times x \times x \times x \times x }{ x \times x \times x \times x }\] now cancel x's
Nnesha
  • Nnesha
when you multiply same bases u should their exponent so that's how we can factor x^6
Nnesha
  • Nnesha
|dw:1433721432895:dw| like this so \[\huge\rm \frac{ x^6 }{ x^4 } = ?\]
anonymous
  • anonymous
x^6-4
Nnesha
  • Nnesha
yes! that's right
Nnesha
  • Nnesha
so x^?
anonymous
  • anonymous
x^2
Nnesha
  • Nnesha
yep right
Nnesha
  • Nnesha
what about y
anonymous
  • anonymous
y^2-5?
Nnesha
  • Nnesha
yes right
anonymous
  • anonymous
or y ^5-2
anonymous
  • anonymous
oh ok
Nnesha
  • Nnesha
nope first one is right you will get negative answer then you have to use another exponent rule \[\huge\rm x^{-m}= \frac{ 1 }{ x^m }\]
anonymous
  • anonymous
so y^-3 = 1/y^-3?
Nnesha
  • Nnesha
look at the exponent rule i gave find ot ur mistake
Nnesha
  • Nnesha
you*
Nnesha
  • Nnesha
let m =3
anonymous
  • anonymous
so 1/x^3?
Nnesha
  • Nnesha
yes right!
anonymous
  • anonymous
okay so is the answe A?
anonymous
  • anonymous
@jigglypuff314 is the answer A?
jigglypuff314
  • jigglypuff314
That's what I got! :)
anonymous
  • anonymous
thnx
anonymous
  • anonymous
can you help with this
anonymous
  • anonymous
Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created? f(x) = one eighth (x - 1)2 - 2 f(x) = -one eighth (x + 1)2 - 2 f(x) = -one sixteenth (x + 1)2 - 2 f(x) = one sixteenth (x - 1)2 + 2
jigglypuff314
  • jigglypuff314
:blinks: you might want to ask that as a separate question ^_^
anonymous
  • anonymous
okay

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