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anonymous

  • one year ago

help @Nnesha

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  1. anonymous
    • one year ago
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    What is the simplified form of 15 times x to the sixth power over 20 times y to the fifth power times the fraction 6 times y-squared over 5 times x to the fourth power ? 9 x-squared over 10 y-cubed 9 x cubed over 10 y-squared 10 x cubed over 9 y-squared 10 x squared over 9 y-cubed

  2. campbell_st
    • one year ago
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    so the question is \[\frac{15x^6}{20y^5} \times \frac{6y^2}{5x^4}\] so if you simplify it you get \[\frac{90x^6y^2}{100x^4y^5}\] start by simplfying 90/100 = then with the powers, use the index law for division, subtract the powers for the same base \[\frac{x^a}{x^b} = x^{a - b}\] if you get a negative power it just indicates a fraction \[x^{-a} = \frac{1}{x^a}\] hope it helps

  3. anonymous
    • one year ago
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    @Nnesha can you help i dont get ot

  4. Nnesha
    • one year ago
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    everything is there! :-) reread that

  5. anonymous
    • one year ago
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    i dont understand it

  6. Nnesha
    • one year ago
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    tell me what part u don't get 4rm that ? i have nothing to add :-)

  7. Nnesha
    • one year ago
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    divide 90/100= ?? keep it in fraction form reduce the fraction

  8. Nnesha
    • one year ago
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    if there are same bases at the denominator and numerator you have to use exponent rule \[\huge\rm \frac{ x^a }{ x^b } = x^{a-b}\]

  9. Nnesha
    • one year ago
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    for example \[\rm \frac{ 3^3 }{ 3^2 } = 3^{3-2}\]

  10. anonymous
    • one year ago
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    okay so i got 9x^3/10y^3

  11. anonymous
    • one year ago
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    like when i used a calculator idk this one is confusing

  12. Nnesha
    • one year ago
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    in other words x^6 can be written as \[\huge\rm \frac{ x \times x \times x \times x \times x \times x }{ x \times x \times x \times x }\] now cancel x's

  13. Nnesha
    • one year ago
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    when you multiply same bases u should their exponent so that's how we can factor x^6

  14. Nnesha
    • one year ago
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    |dw:1433721432895:dw| like this so \[\huge\rm \frac{ x^6 }{ x^4 } = ?\]

  15. anonymous
    • one year ago
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    x^6-4

  16. Nnesha
    • one year ago
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    yes! that's right

  17. Nnesha
    • one year ago
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    so x^?

  18. anonymous
    • one year ago
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    x^2

  19. Nnesha
    • one year ago
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    yep right

  20. Nnesha
    • one year ago
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    what about y

  21. anonymous
    • one year ago
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    y^2-5?

  22. Nnesha
    • one year ago
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    yes right

  23. anonymous
    • one year ago
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    or y ^5-2

  24. anonymous
    • one year ago
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    oh ok

  25. Nnesha
    • one year ago
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    nope first one is right you will get negative answer then you have to use another exponent rule \[\huge\rm x^{-m}= \frac{ 1 }{ x^m }\]

  26. anonymous
    • one year ago
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    so y^-3 = 1/y^-3?

  27. Nnesha
    • one year ago
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    look at the exponent rule i gave find ot ur mistake

  28. Nnesha
    • one year ago
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    you*

  29. Nnesha
    • one year ago
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    let m =3

  30. anonymous
    • one year ago
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    so 1/x^3?

  31. Nnesha
    • one year ago
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    yes right!

  32. anonymous
    • one year ago
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    okay so is the answe A?

  33. anonymous
    • one year ago
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    @jigglypuff314 is the answer A?

  34. jigglypuff314
    • one year ago
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    That's what I got! :)

  35. anonymous
    • one year ago
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    thnx

  36. anonymous
    • one year ago
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    can you help with this

  37. anonymous
    • one year ago
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    Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created? f(x) = one eighth (x - 1)2 - 2 f(x) = -one eighth (x + 1)2 - 2 f(x) = -one sixteenth (x + 1)2 - 2 f(x) = one sixteenth (x - 1)2 + 2

  38. jigglypuff314
    • one year ago
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    :blinks: you might want to ask that as a separate question ^_^

  39. anonymous
    • one year ago
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    okay

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