## anonymous one year ago help @Nnesha

1. anonymous

What is the simplified form of 15 times x to the sixth power over 20 times y to the fifth power times the fraction 6 times y-squared over 5 times x to the fourth power ? 9 x-squared over 10 y-cubed 9 x cubed over 10 y-squared 10 x cubed over 9 y-squared 10 x squared over 9 y-cubed

2. campbell_st

so the question is $\frac{15x^6}{20y^5} \times \frac{6y^2}{5x^4}$ so if you simplify it you get $\frac{90x^6y^2}{100x^4y^5}$ start by simplfying 90/100 = then with the powers, use the index law for division, subtract the powers for the same base $\frac{x^a}{x^b} = x^{a - b}$ if you get a negative power it just indicates a fraction $x^{-a} = \frac{1}{x^a}$ hope it helps

3. anonymous

@Nnesha can you help i dont get ot

4. Nnesha

everything is there! :-) reread that

5. anonymous

i dont understand it

6. Nnesha

tell me what part u don't get 4rm that ? i have nothing to add :-)

7. Nnesha

divide 90/100= ?? keep it in fraction form reduce the fraction

8. Nnesha

if there are same bases at the denominator and numerator you have to use exponent rule $\huge\rm \frac{ x^a }{ x^b } = x^{a-b}$

9. Nnesha

for example $\rm \frac{ 3^3 }{ 3^2 } = 3^{3-2}$

10. anonymous

okay so i got 9x^3/10y^3

11. anonymous

like when i used a calculator idk this one is confusing

12. Nnesha

in other words x^6 can be written as $\huge\rm \frac{ x \times x \times x \times x \times x \times x }{ x \times x \times x \times x }$ now cancel x's

13. Nnesha

when you multiply same bases u should their exponent so that's how we can factor x^6

14. Nnesha

|dw:1433721432895:dw| like this so $\huge\rm \frac{ x^6 }{ x^4 } = ?$

15. anonymous

x^6-4

16. Nnesha

yes! that's right

17. Nnesha

so x^?

18. anonymous

x^2

19. Nnesha

yep right

20. Nnesha

21. anonymous

y^2-5?

22. Nnesha

yes right

23. anonymous

or y ^5-2

24. anonymous

oh ok

25. Nnesha

nope first one is right you will get negative answer then you have to use another exponent rule $\huge\rm x^{-m}= \frac{ 1 }{ x^m }$

26. anonymous

so y^-3 = 1/y^-3?

27. Nnesha

look at the exponent rule i gave find ot ur mistake

28. Nnesha

you*

29. Nnesha

let m =3

30. anonymous

so 1/x^3?

31. Nnesha

yes right!

32. anonymous

okay so is the answe A?

33. anonymous

34. jigglypuff314

That's what I got! :)

35. anonymous

thnx

36. anonymous

can you help with this

37. anonymous

Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created? f(x) = one eighth (x - 1)2 - 2 f(x) = -one eighth (x + 1)2 - 2 f(x) = -one sixteenth (x + 1)2 - 2 f(x) = one sixteenth (x - 1)2 + 2

38. jigglypuff314

:blinks: you might want to ask that as a separate question ^_^

39. anonymous

okay