A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
help solving quadratic equation 8x+60=x^2+15x
Help please please cx
anonymous
 one year ago
help solving quadratic equation 8x+60=x^2+15x Help please please cx

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2set it equal to 0 so move 8x+60 to the right side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 0=x^2+15x 8x+60?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2nope 60 is positive at left side so subtract 60 both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh so 0=x^2+15x 8x60?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right now combine LIKE terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00=x^2+15x 8x60 ^ 7 0=x^2+7x60

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha what do i do next?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes that's right now you can use quadratic formula to solve for x \[\huge\rm \frac{ { }b \pm \sqrt{b^2 4ac} }{ {2a} }\] or you can factor it \[ \large\rm \color{red}{1}x^2 +\color{Red}{ 7}x \color{reD}{ 60} = 0\]\[\large\rm \color{blue}{A}x^2 +\color{blue}{B}x+\color{blue}{C}=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the factoring one seems simpler lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think thats what im suppose to do, is to factor it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright to factor this one find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term b

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2A is leading coefficient C is constant term :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yep right so bec leading coefficient is just one GREAT! just write those two numbers with x (x + 1st number)(x+ 2nd number)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right + times 5 equal  so (x5)(x+12)=0

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2if you have to solve for x set both parentheses equal to zero solve for x like this x5 =0 and x+12 =0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh ok, i would get 5 and 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you!, is that it?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yep factors are (x5)(x+12) solution or x value are 5 and 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much! Cx
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.