anonymous
  • anonymous
help solving quadratic equation 8x+60=x^2+15x Help please please cx
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Nnesha
  • Nnesha
set it equal to 0 so move 8x+60 to the right side
anonymous
  • anonymous
so 0=x^2+15x- 8x+60?
Nnesha
  • Nnesha
nope 60 is positive at left side so subtract 60 both sides

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More answers

anonymous
  • anonymous
ohhh so 0=x^2+15x- 8x-60?
Nnesha
  • Nnesha
yes right now combine LIKE terms
anonymous
  • anonymous
0=x^2+15x- 8x-60 ^ 7 0=x^2+7x-60
anonymous
  • anonymous
@Nnesha what do i do next?
Nnesha
  • Nnesha
yes that's right now you can use quadratic formula to solve for x \[\huge\rm \frac{ {- }b \pm \sqrt{b^2 -4ac} }{ {2a} }\] or you can factor it \[ \large\rm \color{red}{1}x^2 +\color{Red}{ 7}x \color{reD}{- 60} = 0\]\[\large\rm \color{blue}{A}x^2 +\color{blue}{B}x+\color{blue}{C}=0\]
anonymous
  • anonymous
the factoring one seems simpler lol
anonymous
  • anonymous
i think thats what im suppose to do, is to factor it
Nnesha
  • Nnesha
alright to factor this one find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term b
Nnesha
  • Nnesha
A is leading coefficient C is constant term :-)
anonymous
  • anonymous
-5 and 12
Nnesha
  • Nnesha
yep right so bec leading coefficient is just one GREAT! just write those two numbers with x (x + 1st number)(x+ 2nd number)
anonymous
  • anonymous
(x+(-5))(x+12)
Nnesha
  • Nnesha
yes right + times -5 equal - so (x-5)(x+12)=0
Nnesha
  • Nnesha
if you have to solve for x set both parentheses equal to zero solve for x like this x-5 =0 and x+12 =0
anonymous
  • anonymous
ohh ok, i would get 5 and -12
Nnesha
  • Nnesha
yep that's right!
anonymous
  • anonymous
Thank you!, is that it?
anonymous
  • anonymous
the answer
Nnesha
  • Nnesha
yep factors are (x-5)(x+12) solution or x value are 5 and -12
anonymous
  • anonymous
Thank you so much! Cx
Nnesha
  • Nnesha
my pleasure :-)

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