## anonymous one year ago If AR = 12 m and RE = 4 m, what is the ratio of the areas of ARH and AES? 3 : 4 4 : 9 9 : 16 9 : 1

1. anonymous

2. anonymous

The ratio of linear measurements squared will find you the ratio of area measurements, but first you must simplify:$\frac{ 12 }{ 4 }=\frac{ 3 }{ 1 }$ Then you square$\frac{ 3^{2} }{ 1^{^{2}} }$

3. anonymous

Took me a while to get the symbols right this time :)

4. anonymous

4:9? @danielgarcia413

5. anonymous

Close, 9:1

6. anonymous

@danielgarcia413 Thanks, im kind of starting to get this stuff!

7. anonymous

No problem, good to hear!