How much would $300 invested at 4% interest compounded monthly be worth after 8 years? Round your answer to the nearest cent. here's the equation: A(t)=P(1+r/n)^nt i just don't know what to put where please help

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How much would $300 invested at 4% interest compounded monthly be worth after 8 years? Round your answer to the nearest cent. here's the equation: A(t)=P(1+r/n)^nt i just don't know what to put where please help

Mathematics
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What I mean to ask is, what do you think each variable in the formula means?
Obviously t is in years, so 8 = t. You probably know that much at least.

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is it a(8)=300(1+.06/1)^8 ??
The 300 and the 8 is correct.
is that is?
it?*
There's more to it of course.
Okay, so the P is for the principal, which you figured out is $300. The r is the interest rate which is 4% or .04. And the n represents number of times compounded. You figure that out by multiply 8 years times 12 months per year. So n = 96.
so 8=300(1+.04/1)^96?
Where do you get the "1" underneath the fraction? Isn't that supposed to be "n". What did we say n equals?
Actually, n = 12, not 96
oh oops. 8=300(1+.04/12)^96 ?
So n represents number of times compounded per year which is 12. So A(8) = 300(1.04/12)^{96} is correct.
is it 1.04 for the numerator? or 1+ .04/12?
Actually you have it right it's 1 + .04/12
I admit, I'm a little distracted atm. Not fully paying attention.
okay. how do i solve it?
At this point, it's just plug and play if you have the right calculator you should be able to calculate A(8).
am i solving for a?
You're finding A(8). Everything on the right side of the equation only has to be calculated.
\[A(8)=300(1+\frac{ .04 }{ 12 })^96\]
like this? i tried to put the 6 up next to the 9 but it didn't work
Use brackets
\(A(8)=300\left(1+\dfrac{ .04 }{ 12 }\right)^{96}\)
i keep getting 51.61
the answer choices are a) $412.92 b) $410.57 c) $308.10 d) $484.25
do you get 51.61?
Hang on
I get 412.918...
oh! okay. i see how you got that. thank you!!
You're Welcome bro.

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