A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
@jim_thompson5910
anonymous
 one year ago
@jim_thompson5910

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using a directrix of y = 2 and a focus of (1, 6), what quadratic function is created? f(x) = one eighth (x  1)2  2 f(x) = one eighth (x + 1)2  2 f(x) = one sixteenth (x + 1)2  2 f(x) = one sixteenth (x  1)2 + 2

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0no one likes these conic section problems, they are not that hard

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433727883608:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0parabola opens up, and the vertex is half way between \((1,6)\) and \(y=2\) so it is at \((1,3)\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0general form will be \[f(x)=\frac{1}{4p}(xh)^2+k\] so you have \[f(x)=\frac{1}{4p}(x1)^2+6\] all you need is \(p\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0\(p\) is the distance between the vertex and the focus (or the vertex and the directrix) which is 3, so final answer is \[f(x)=\frac{1}{12}(x1)^2+6\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.