## anonymous one year ago @jim_thompson5910

1. anonymous

Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created? f(x) = one eighth (x - 1)2 - 2 f(x) = -one eighth (x + 1)2 - 2 f(x) = -one sixteenth (x + 1)2 - 2 f(x) = one sixteenth (x - 1)2 + 2

2. anonymous

@Nnesha

3. anonymous

@misty1212

4. anonymous

@timo86m

5. misty1212

HI!!

6. misty1212

no one likes these conic section problems, they are not that hard

7. misty1212

|dw:1433727883608:dw|

8. misty1212

parabola opens up, and the vertex is half way between $$(1,6)$$ and $$y=-2$$ so it is at $$(1,3)$$

9. misty1212

general form will be $f(x)=\frac{1}{4p}(x-h)^2+k$ so you have $f(x)=\frac{1}{4p}(x-1)^2+6$ all you need is $$p$$

10. misty1212

$$p$$ is the distance between the vertex and the focus (or the vertex and the directrix) which is 3, so final answer is $f(x)=\frac{1}{12}(x-1)^2+6$