Find an equation of the tangent line to the curve at the given point. y = sin 5x + sin^2 5x, (0, 0) I got 5x but it was wrong please help me

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Find an equation of the tangent line to the curve at the given point. y = sin 5x + sin^2 5x, (0, 0) I got 5x but it was wrong please help me

Calculus1
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y'= ??
cos5x+2sin5x?
Forgot chain rule.

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it's not that but I got what you have. hahahaha....
\(y' = cos(5x)\cdot5 +2sin(5x)\cdot cos(5x)\cdot5\) \(y' = 5cos(5x) + 10sin(5x)cos(5x)\)
@Concentrationalizing some more steps, you will get what he got and it is wrong (according to him) :)
but I don't know how it is wrong!! or you should write y = 5x @gaba
Plug in 0 into the derivative: \(y' = 5cos(0) + 10sin(0)cos(0)\) \(y' = 5\) Hmm....question is typed incorrectly?
i needed to type it as y=5x! thank you!!
oh, lol. Okay, cool.
hahahaha...................... it's fun.

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