## anonymous one year ago Find an equation of the tangent line to the curve at the given point. y = sin 5x + sin^2 5x, (0, 0) I got 5x but it was wrong please help me

1. Loser66

y'= ??

2. anonymous

cos5x+2sin5x?

3. anonymous

Forgot chain rule.

4. Loser66

it's not that but I got what you have. hahahaha....

5. anonymous

$$y' = cos(5x)\cdot5 +2sin(5x)\cdot cos(5x)\cdot5$$ $$y' = 5cos(5x) + 10sin(5x)cos(5x)$$

6. Loser66

@Concentrationalizing some more steps, you will get what he got and it is wrong (according to him) :)

7. Loser66

but I don't know how it is wrong!! or you should write y = 5x @gaba

8. anonymous

Plug in 0 into the derivative: $$y' = 5cos(0) + 10sin(0)cos(0)$$ $$y' = 5$$ Hmm....question is typed incorrectly?

9. anonymous

i needed to type it as y=5x! thank you!!

10. anonymous

oh, lol. Okay, cool.

11. Loser66

hahahaha...................... it's fun.