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anonymous
 one year ago
what is the focus of the parabola given by the equation y=x^22x3?
a. (4,15/4)
b. (1,4)
c. (1,4)
d. (1,15/4)
e. (1,15/4)
anonymous
 one year ago
what is the focus of the parabola given by the equation y=x^22x3? a. (4,15/4) b. (1,4) c. (1,4) d. (1,15/4) e. (1,15/4)

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1i swear i just saw this question a second ago

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1trick is to write it as \[y+3=x^22x\] then complete the square on the left do you know how to do that?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lol i mean on the RIGHT

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i dont :( @misty1212

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok ready? it is not hard

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok and \(1^2=1\) so we go right from \[y+3=x^22x\] to \[y+3+1=(x1)^2\] or \[y+4=(x1)^2\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1now we need the focus, but first we need the vertex the vertex we see from our eyeballs is \((1,4)\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1then we compare to the standard form \[4p(yk)=(xh)^2\] and see that in this case \(4p=1\)so \(p=\frac{1}{4}\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so we travel \(\frac{1}{4}\) units up from \((1,4)\) and get to \((1,\frac{15}{4})\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes please thank you @misty1212
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