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anonymous
 one year ago
.hjh
anonymous
 one year ago
.hjh

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, the average rate of change between two points is simply the slope between them. So I assume you know slope to be determined by \[\frac{ y_{2}  y_{1} }{ x_{2}x_{1} }\] So in the first statement, if the average rate of change, the slope, is 0, what must be true about \[\frac{ y_{2}y_{1} }{ x_{2}x_{1} }\]?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know xc ... maybe between 3 and 3 there are solutions?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, if the average rate of change is 0 then the slope is 0. Which means \[\frac{ y_{2}  y_{1} }{ x_{2}x_{1} } = 0\] Basically, how can we make that fraction for slope =0?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would the demominaters be 3 and 3? 3(3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, they would be. So you would have \[\frac{ y_{2}y_{1} }{ 6 } = 0\] So what does that say about y_2 and y_1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That there not identified yet?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433728163730:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, not trying to tease or anything, just wanted you to see it. Well, the only way a fraction can be 0 is if the numerator is 0. Which means \(y_{2}  y_{1} = 0\) \(y_{1} = y_{2}\) The idea is that the y coordinate of both points has to be the same in order for the average rate of change to be 0. That make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Kinda, it makes the reasoning for why its 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would that explain tuckers part on why he's correct? or is there more to tuckers reasoning :o

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, exactly. So the first person is essentialy saying the ycoordinates for both points are the same. It doesnt matter what they are, we just want them to be the same. So, for example, lets say our yvalue is 0. So we would have the points (3,0) and (3,0).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As for the 2nd person, considering the graph between 3 and 3 we know it'll go up and then back down. But at the same time, we also want the graph to start and begin at the same yvalue. So we want something like this. dw:1433728476305:dw So, the best example of how this is possible is if the graph is a parabola. But really, any continuous function that has the same ycoordinate at x = 3 and x = 3 and is not a line will make them both correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok! That makes since, and yea i thought it would be a parabola, thanks again! cx xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, I guess it also has to be going up in between 3 and 3, lol. So I guess it cant be EVERYTHING with xintercepts at 3 and 3, but you get the idea.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yea lol, thats all i think of when i hear " up and down", and is it ok if i write out the answers and you read to see if it souds right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0* Tucker says that for the function, between x = 3 and x = 3, the average rate of change is 0* Here Tucker says that between 3 and 3 x coordinates that the average rate of change is 0.. the slope is y2−y1/x2−x1 and if you plug in the x coordinates you get y2−y1/6=0.... whats true is that the xcoordinates are 3 and 3, whats true about y is y2−y1=0 so y1=y2, the y coordinate of both points has to be the same in order for the average rate of change to be 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry that took forever, but thats tuckers reasoning

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It doesnt need to be that wordy, that was just me trying to explain the idea :P Really, all you need to say is something like this: "Tucker can be correct as long as the average of change is 0. As in the slope between the points (3,y1) and (3,y2) is 0. This is only true if y1 = y2." I dont think you really need to go into any more detail than that. I would think any detail left out from that is stuff youre assumed to know and dont really need to explain.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok lol, yea i was writing it like " wait... should i include this O.o" lol and thanks! ill do the other person, and less wordy lol cx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, pretty much any minimal conditions that would make the statement true :P In the end, we dont even care about the xcoordinates. The xcoordinates could be anything, but the fact that we know the rate of change has to be 0 just tells us the ycoordinates have to be equal.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Karly is correct also because if you draw a graph between 3 and 3 we know it'll go up and then back down, example parabola

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, have to phrase that a little differently, just be careful. The way you phrased it, you said if we draw a graph between 3 and 3. Just by drawing that graph, that doesnt mean it will go up and then down. Just trying to be careful with the wording. We want to state a condition that makes both of them correct. "Karly claims the goes up through a turning point and then comes back down. This won't contradict Tucker's statement as long as the graph has the same ycoordinate at x = 3 and x = 3. An example where this could easily be true is a parabola." Not trying to be super picky or mean or anything, I guess Im almost making sure the English is good now and not the math, haha.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No it's ok, I don't want to do bad Cx and thank you so much, your really a big help! cx
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