anonymous
  • anonymous
Gyroscopic procession question
Physics
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anonymous
  • anonymous
Gyroscopic procession question
Physics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
|dw:1433730100954:dw|
anonymous
  • anonymous
|dw:1433730137138:dw|
anonymous
  • anonymous
After drawing it out and thinking about it, it seems that things cancel out.

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anonymous
  • anonymous
|dw:1433730534260:dw| I was wondering is something like this would result in some sort of upward force.
anonymous
  • anonymous
|dw:1433730674626:dw|
anonymous
  • anonymous
For the arrows mixed up.
Kainui
  • Kainui
So is this the right picture then? |dw:1433730753297:dw|
anonymous
  • anonymous
Hmmm, I keep confusing myself with orientation
anonymous
  • anonymous
They're spinning in opposite directions.
anonymous
  • anonymous
I'm wondering, since they both balance on the beam, is there still procession from gravity?
Kainui
  • Kainui
Well precession is a change in the angular momentum vector which is torque, so maybe we can work it out with some math, I'm not really sure what to do yet but I'll spit out what equations I know. \[\large \bar \tau = \frac{d \bar L}{d t} \] \[\large \bar L = \bar r \times \bar \omega\] \[\large \frac{d \bar L}{dt} = \frac{d \bar r}{d t} \times \bar \omega + \bar r \times \frac{d \bar \omega}{dt}=\bar r \times \bar \alpha = \bar \tau\]
Kainui
  • Kainui
Hmmm that doesn't seem quite right I think I've left somthing out
anonymous
  • anonymous
So procession is a torque that is done in reaction to a torque on the axis of rotation?
anonymous
  • anonymous
Are you confusing angular velocity with angular momentum?
Empty
  • Empty
|dw:1434154506359:dw|

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