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anonymous
 one year ago
Gyroscopic procession question
anonymous
 one year ago
Gyroscopic procession question

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433730100954:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433730137138:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0After drawing it out and thinking about it, it seems that things cancel out.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433730534260:dw I was wondering is something like this would result in some sort of upward force.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433730674626:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the arrows mixed up.

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0So is this the right picture then? dw:1433730753297:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm, I keep confusing myself with orientation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0They're spinning in opposite directions.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm wondering, since they both balance on the beam, is there still procession from gravity?

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Well precession is a change in the angular momentum vector which is torque, so maybe we can work it out with some math, I'm not really sure what to do yet but I'll spit out what equations I know. \[\large \bar \tau = \frac{d \bar L}{d t} \] \[\large \bar L = \bar r \times \bar \omega\] \[\large \frac{d \bar L}{dt} = \frac{d \bar r}{d t} \times \bar \omega + \bar r \times \frac{d \bar \omega}{dt}=\bar r \times \bar \alpha = \bar \tau\]

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm that doesn't seem quite right I think I've left somthing out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So procession is a torque that is done in reaction to a torque on the axis of rotation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you confusing angular velocity with angular momentum?
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