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anonymous

  • one year ago

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  1. Luigi0210
    • one year ago
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    Do you know the vertex equation?

  2. Luigi0210
    • one year ago
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    To go from \(x^6\) to \(-3(x+4)^6-8\) you need to do some shifting and turning, use the vertex form to help: \(f(x)=a(x-h)^2+k \) where the vertex is (h, k) and a determines the expansion/shrink.

  3. anonymous
    • one year ago
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    how would i plug x^6 into the vertex form ? or would i put the second equation into the vertex form? :o

  4. anonymous
    • one year ago
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    wait nvm it already is in vertex form

  5. Luigi0210
    • one year ago
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    If you look at the graphs, it might be a bit hard to see but as you can see the graph was reflected http://prntscr.com/7eetq9 and probably has a vertex at (-4, 8)

  6. anonymous
    • one year ago
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    Any addition or subtraction represents a shift. So in this case you have +4 and a -8. Any multiplication represents some sort of stretch or compression. If the multiplication is by a negative value it will also be a reflection. The way I kind of explain it is to say is your value "trapped" with x or not? As in can you freely move that number around. So examples of "trapped" are \((x-1)^{2}\) \(\sqrt{x-6}\) \(|x+2|\) Where your numbers are being bounded by some sort of grouping symbol. So, if your transformations are not bound by a grouping symbol, they will affect y-values. So for us, the -3 multiplication and the -8 subtraction are applied to y-values. The +4 is bounded and trapped with x, so it will be the only thing affecting x-values. Now, transformations that affect y-values do as they look like they might do. If it's a +3 shift, things will go up 3. If it's a multiplication by 2, all the y-values will be multiplied by 2. Now the transformations that affect x-values, the "trapped" ones, kind of do the opposite. If it's a +5, you go left 5, more into the negative values for x. And if you multiply by 2, all the x-values shrink by a factor of 2 (or are multiplied by 1/2 you can say). So after all that, let's put everything together. Now, we want to consider multiplicative transformations first. The only one of those is the -3. So all the y-values of x^6 were multiplied by -3. In terms of transformations, this represents a reflection about the x-axis and a stretch by a factor of 3. After that, the graph was shifted 4 to the left and down 8.

  7. anonymous
    • one year ago
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    You're welcome :)

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