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Curry

  • one year ago

Question with circuits

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  1. Curry
    • one year ago
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  2. Curry
    • one year ago
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    @freckles

  3. Curry
    • one year ago
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    @sasogeek @ganeshie8

  4. hwyl
    • one year ago
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    what do you know so far?

  5. Curry
    • one year ago
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    hmm, I know that I should set Rt = Rl to find max power transfer.

  6. Curry
    • one year ago
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    So i started by doing source transformation of 50ohm resistor and Vs and then combined the capacitor value, and then did another source transformation to get into a series circuit. and then i equated the resistor||capacitor + inductor to R load.

  7. Curry
    • one year ago
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    @UnkleRhaukus

  8. Curry
    • one year ago
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    @hwyl

  9. kropot72
    • one year ago
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    The notes here give you the required theory: http://www.usna.edu/Users/cs/vincent/suppnotes/EE301Topic24.pdf

  10. kropot72
    • one year ago
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    Maximum power is transformed when the Thevenin resistance of the source is equal to the resistance of the load (which is 20 ohms in the question). The Thevenin impedance of the source is found from: \[\large Z _{th}=\frac{R}{1+(\omega CR)^{2}}-\frac{j \omega C R^{2}}{1+(\omega CR)^{2}}\] Now you need to put the resistive part of the above Thevenin impedance equal to 20 ohms and plug in R = 50 ohms and omega = 100. Then solve for the value of C. \[\large \frac{50}{1+(100\times C \times 50)^{2}}=20\]

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