## Jravenv one year ago Would someone kindly give their help? screencap in comments.

1. Jravenv

2. kropot72

To solve this, you need to remember that when dividing powers of terms with the same base you need to subtract the indices. For example $\large \frac{w^{6} x^{4}}{w^{2} x^{3}}=w^{(6-2)}x^{(4-3)}=w^{4}x$

3. Jravenv

I don't know how to do that :/

4. kropot72

$\large \frac{4x^{3} y^{4}}{-8xy^{2}}=\frac{4}{-8} \times x^{(3-1)}y^{(4-2)}=?$

5. Jravenv

This is too complicated for me, can you help me break it down?

6. kropot72

Can you subtract 1 from 3, and subtract 2 from 4?

7. Jravenv

2 and 2 so yes

8. kropot72

Correct. And what is 4/-8?

9. Jravenv

-1/2

10. UnkleRhaukus

yeah, and what isare (3-1) ? , (4-2) ?

11. UnkleRhaukus

yeah you had 2 and 2, so... $\large \frac{4x^{3} y^{4}}{-8xy^{2}}\\ =\frac{4}{-8} \times x^{(3-1)}y^{(4-2)}\\ =\frac{-1}2x^2y^2$

12. Jravenv

I don't get that :( I'm sorry I have a horrible instructor

13. kropot72

What part don't you get? You have correctly answered the sections that were broken down for you.

14. Jravenv

The formatting makes my brain shut down

15. Jravenv

I don't get it

16. kropot72

So the correct choice has -1/2, x^2 and y^2.

17. anonymous

4x3y4/8xy2 Reduce the expression by cancelling the common factors. More Steps Factor 4 out of 4x3y4. 4(x3y4)−8xy2 Rewrite the expression. x3y4−2xy2 x3y4−2xy2 Reduce the expression by cancelling the common factors. More Steps Factor x out of x3y4. x(x2y4)−2xy2 Rewrite the expression. x2y4−2y2 x2y4−2y2 Reduce the expression by cancelling the common factors. More Steps Factor y2 out of x2y4. y2(x2y2)−2y2 Rewrite the expression. x2y2/-2 x2y2/-2 Move the negative in front of the fraction. −x2y2/2

18. Jravenv

Thank you all so much. I get it so much more now.

19. kropot72

You're welcome :)