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anonymous

  • one year ago

PLEASE HELP

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  1. anonymous
    • one year ago
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  2. UnkleRhaukus
    • one year ago
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    \[\frac92\log_2(x)=9\] multiply both sides by 2/9, to get rid of that fraction on the left hand side

  3. anonymous
    • one year ago
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    so 5.3399?

  4. anonymous
    • one year ago
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    i entered it and its wrong

  5. UnkleRhaukus
    • one year ago
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    \[\frac92\log_2(x)=9\\ \frac29\times\frac92\log_2(x)=\frac29\times9\\ \cdots=\cdots\]

  6. UnkleRhaukus
    • one year ago
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    can you simplify both sides now?

  7. anonymous
    • one year ago
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    log2(x)=1?

  8. UnkleRhaukus
    • one year ago
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    you've got the left hand side right, but check that right hand side again

  9. anonymous
    • one year ago
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    Im not sure what i did wrong

  10. UnkleRhaukus
    • one year ago
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    \[\frac29\times9=\frac2{\cancel 9}\times\cancel 9\]

  11. anonymous
    • one year ago
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    log2(x)=2?

  12. UnkleRhaukus
    • one year ago
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    right ! now we use the definition of a log \[\log_b a = c\iff a=b^c\]

  13. anonymous
    • one year ago
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    log2 (2) = 1?

  14. UnkleRhaukus
    • one year ago
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    you had \[\log_2(x) = 2\] so \[x = . . . \]

  15. anonymous
    • one year ago
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    im so confused

  16. UnkleRhaukus
    • one year ago
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    \[\log_b(a) = c\iff a=b^c\] \[\log_2(x) = 2\iff x=?^{??}\]

  17. anonymous
    • one year ago
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    2

  18. UnkleRhaukus
    • one year ago
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    what is the final equation x =

  19. anonymous
    • one year ago
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    i dont know!! how do i fnid log2(x)=2

  20. UnkleRhaukus
    • one year ago
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    Use the definition for example \[\log_{10}(A) = 3 \iff A = 10^3 = 1000\]

  21. anonymous
    • one year ago
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    ohhhh 4?

  22. UnkleRhaukus
    • one year ago
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    yeah that is the final answer for x

  23. anonymous
    • one year ago
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    i dont get it, the computer says its .25

  24. UsukiDoll
    • one year ago
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    it's probably due to the confusion of the regular 2 being typed out and the subscript 2... .25 = 1/4 . so the computer claims that it's 1/4 -> .25?!

  25. UnkleRhaukus
    • one year ago
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    oh it is meant to equal -9 not 9

  26. UnkleRhaukus
    • one year ago
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    whoops

  27. UsukiDoll
    • one year ago
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    lol latex typo

  28. UnkleRhaukus
    • one year ago
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    \[\frac92\log_2(x)=-9\\ \frac29\times\frac92\log_2(x)=\frac29\times-9\\ \cdots=\cdots\]

  29. UsukiDoll
    • one year ago
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    I see ... \[\log_2(x) = -2\]

  30. UsukiDoll
    • one year ago
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    \[\log(x) = 2^{-2}\] \[\frac{1}{2^2} \rightarrow \frac{1}{4}\]

  31. anonymous
    • one year ago
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    ohhhhh makes sense

  32. UsukiDoll
    • one year ago
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    also known as .25 in decimal form

  33. UnkleRhaukus
    • one year ago
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    (sorry bout that @Polkapen )

  34. anonymous
    • one year ago
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    i have one more question

  35. UsukiDoll
    • one year ago
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    I'm about to faint...sorry I have yet to eat dinner. ~_~

  36. anonymous
    • one year ago
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    oh ok

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