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anonymous

  • one year ago

FAN AND MEDAL The number of marbles of different colors stored in a hat is listed below: 8 red marbles 10 green marbles 6 blue marbles Without looking in the hat, Tessa takes out a marble at random. She replaces the marble and then takes out another marble from the hat. What is the probability that Tessa takes out a blue marble in both draws? fraction 1 over 16 fraction 1 over 12 fraction 1 over 4 fraction 1 over 2

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  1. anonymous
    • one year ago
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    @danicap @GreatGuy

  2. ankit042
    • one year ago
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    prob of blue marble =8/(8+10+6) Now there is a replacement involved so we will have 8/24 * 8/24

  3. anonymous
    • one year ago
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    @MrNood leave

  4. ankit042
    • one year ago
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    sorry it should be 6/24

  5. anonymous
    • one year ago
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    so c

  6. MrNood
    • one year ago
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    there are 24 marbles altogether she has 6 in 24 chances of drawing blue on the first time (write that as a simper fraction) the second time is INDEPENDENT of the first - so the chances are the same both times (she replaces the original blue one) so the chances of 2 independent 6 in 24 events is???

  7. MrNood
    • one year ago
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    it is not c

  8. welshfella
    • one year ago
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    first simplify 6/24

  9. anonymous
    • one year ago
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    and its c

  10. MrNood
    • one year ago
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    I have to be persistent her: you are not helping by giving wrong answers it is not c

  11. welshfella
    • one year ago
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    no - there are 2 draws probability of 1 draw = 1/4 you multiply probabilities for 2 draws

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