If you have a 45.0 V battery connected to a 10.0 Ω resistor and a 5.00 Ω resistor in series, what will be the total power output in the circuit? A. 45.0 W B. 135 W C. 203 W D. 405 W

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If you have a 45.0 V battery connected to a 10.0 Ω resistor and a 5.00 Ω resistor in series, what will be the total power output in the circuit? A. 45.0 W B. 135 W C. 203 W D. 405 W

Physics
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total resistance is: R= 10+ 5=...
15!
ok! so current is: I=45/15=...

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Other answers:

3!
ok! Then the dissipated power is: W= I* V= 3*45=...watts
135!so our solution is choice B? :O
yes! since it is the outputted power
ooh okie! thank you!!:)
:)

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