(y3)^4

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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is it y7?
y^7 *
is that supposed to be \((y^3)^4\)?

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Other answers:

yes
When you multiply 2 powers, you add them. So say you have \(x^3\times x^2\), you'd get \(x^5\). BUT when you take a power to a power, you have to multiply them. So \((x^3)^2\) would be \(x^6\). Does that make sense? In your case, you're taking a power to a power. So, rethink your answer and let me know what you get.
y^12 ?
Yep! Good job.
thank you
You're welcome. :)
I'm sorry, I have to go, but just use what I said earlier.

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