anonymous
  • anonymous
Please help :(
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
What is the value of x? Round your answer to the nearest tenth if necessary.
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Nnesha
  • Nnesha
Pythagorean theorem \[\huge\rm a^2 + b^2 = c^2 \] c is the longest side of right triangle which is hypotenuse so substitute values then solve :-)
anonymous
  • anonymous
I got 89 @Nnesha

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Nnesha
  • Nnesha
x^2 = 89 right x = what ?
anonymous
  • anonymous
what?
Nnesha
  • Nnesha
yep what ??
Nnesha
  • Nnesha
Pythagorean theorem \[\huge\rm (5)^2 + (8)^2 = x^2 \] 25+64 = x^2 you need x not x^2
anonymous
  • anonymous
oh, okay
anonymous
  • anonymous
okay, I got 89=x^2?
Nnesha
  • Nnesha
yes right now solve for x how would you cancel square of x ?
anonymous
  • anonymous
by moving the decimal?
Nnesha
  • Nnesha
take square root both sides to cancel square
anonymous
  • anonymous
how do I do that
Nnesha
  • Nnesha
\[\huge\rm \sqrt{x} = x^\frac{ 1 }{ 2 }\] like this so take square root of x^2 and 89

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