anonymous
  • anonymous
Please help :(
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What is the value of x? Round your answer to the nearest tenth if necessary.
1 Attachment
Nnesha
  • Nnesha
Pythagorean theorem \[\huge\rm a^2 + b^2 = c^2 \] c is the longest side of right triangle which is hypotenuse so substitute values then solve :-)
anonymous
  • anonymous
I got 89 @Nnesha

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Nnesha
  • Nnesha
x^2 = 89 right x = what ?
anonymous
  • anonymous
what?
Nnesha
  • Nnesha
yep what ??
Nnesha
  • Nnesha
Pythagorean theorem \[\huge\rm (5)^2 + (8)^2 = x^2 \] 25+64 = x^2 you need x not x^2
anonymous
  • anonymous
oh, okay
anonymous
  • anonymous
okay, I got 89=x^2?
Nnesha
  • Nnesha
yes right now solve for x how would you cancel square of x ?
anonymous
  • anonymous
by moving the decimal?
Nnesha
  • Nnesha
take square root both sides to cancel square
anonymous
  • anonymous
how do I do that
Nnesha
  • Nnesha
\[\huge\rm \sqrt{x} = x^\frac{ 1 }{ 2 }\] like this so take square root of x^2 and 89

Looking for something else?

Not the answer you are looking for? Search for more explanations.