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anonymous
 one year ago
Please help!
A student increases the temperature of a 556 cm3 balloon from 278 K to 231 K. Assuming constant pressure, what should the new volume of the balloon be?
417 cm3
462 cm3
924 cm3
376 cm3
anonymous
 one year ago
Please help! A student increases the temperature of a 556 cm3 balloon from 278 K to 231 K. Assuming constant pressure, what should the new volume of the balloon be? 417 cm3 462 cm3 924 cm3 376 cm3

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Luigi0210 @tkhunny @Nnesha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if the pressure is constant then the balloon will follow Charles' law just use V/T = constant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not very good at chemistry I wouldn't be able to explain..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm just asking how did you arrived at the answer without solving it I gave you the formula and the theory... try to solve with it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wasn't able to figure it out.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0556*231/278=462 cm^3? Is this correct?

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433792552914:dw

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0Where V1 = 556 Cm3 which u wuld hav to convert to atm 278 K is T1 and 231 is T2 now use the equation to solve for V2 or the new volume. Do u understand?
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