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anonymous
 one year ago
An electric heating coil will consume 6.0*10^2 W of power when it is connected to a 120V outlet. A greenhouse operator has 2 such coils, and she wants to construct a single heater using the two coils to keep her small greenhouse at a temperature of 50.0 C during the winter months. For how many hours must this heater (2 coils) operate per day if an average of 1.5*10^7 J of energy are required each winter day to maintain the desired temperature given that the coils are connected
a) in series
b) in parallel
anonymous
 one year ago
An electric heating coil will consume 6.0*10^2 W of power when it is connected to a 120V outlet. A greenhouse operator has 2 such coils, and she wants to construct a single heater using the two coils to keep her small greenhouse at a temperature of 50.0 C during the winter months. For how many hours must this heater (2 coils) operate per day if an average of 1.5*10^7 J of energy are required each winter day to maintain the desired temperature given that the coils are connected a) in series b) in parallel

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you think the answer is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I really am not sure... but if I recall correctly, there is something about the parallel taking less time?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0wait i'll give the solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just show me the process step by step please

radar
 one year ago
Best ResponseYou've already chosen the best response.1First step. Convert the 15,000,000 J to watthours. Use this link if you want.: http://www.unitconversion.org/energy/joulestowatthoursconversion.html

radar
 one year ago
Best ResponseYou've already chosen the best response.1Next, Step 2. Calculate the wattage for both parallel and series connection. For parallel operation all is needed is to multiply the single coil power by 2 or 1200 Watts. For the series arrangement each coils is only getting 60 volts (1/2 of the 120) and since power = (e^2)/R it would be getting 1/4 their rated power or 600/4 for each coil or a total of 300 watts. You now have the needed info to make a determination of how many hours a day is needed for each configuration. The problem is asking for hours not what configuration. It is not an A or B thing lol.

radar
 one year ago
Best ResponseYou've already chosen the best response.1You will find that the series configuration will require 4 times the hours per day than the parallel configuration does

radar
 one year ago
Best ResponseYou've already chosen the best response.1How,some,ever, the cost remains the same.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you for your answer, I really appreciate it =D
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