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Mathematics
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You need to know these rules of logs: \(\Large \log_b \dfrac{x}{y} = \log_bx - \log_b y\) \(\Large \log_b x^n = n \log_b x\) Use the first rule first. What do you get?
so that means that in the second part of the equation, it always has to be subtracting... okay. that takes 2 answers off my list.

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would it be \[\log_{4}8-2\log_{4}x \]
someone please help me
You're doing just fine.
did i get the right answer??:D
Yea you're right :_
No, that would be dividing 8 squared by c
I mean *x lol
Look at the earlier post by mathstudent55, you are supposed to be subtracting the divisor.
Did you choose D "did i get the right answer??:D"
no, thats a super smiley face, haha. i choose C and it was correct
O..K that is correct!
Applying the first rule we get: \( \Large \log_4 \dfrac{8}{x^2} = \log_4 8 - \log_4 x^2\) Applying the second rule we get: \( \Large \log_4 \dfrac{8}{x^2} = \log_4 8 - 2 \log_4 x\)
You are correct. Good job!
Sorry about that I guess I am not "hip" to internet speak lol.
I thought you were on track that is why I said you are doing fine, then you posted that and it threw me off.
@mathstudent55 Just a problem in "internet slang"

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