anonymous
  • anonymous
please help, question below
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
mathstudent55
  • mathstudent55
You need to know these rules of logs: \(\Large \log_b \dfrac{x}{y} = \log_bx - \log_b y\) \(\Large \log_b x^n = n \log_b x\) Use the first rule first. What do you get?
anonymous
  • anonymous
so that means that in the second part of the equation, it always has to be subtracting... okay. that takes 2 answers off my list.

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anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
would it be \[\log_{4}8-2\log_{4}x \]
anonymous
  • anonymous
someone please help me
anonymous
  • anonymous
@Luigi0210
radar
  • radar
You're doing just fine.
anonymous
  • anonymous
did i get the right answer??:D
anonymous
  • anonymous
@radar
Luigi0210
  • Luigi0210
Yea you're right :_
radar
  • radar
No, that would be dividing 8 squared by c
radar
  • radar
I mean *x lol
radar
  • radar
Look at the earlier post by mathstudent55, you are supposed to be subtracting the divisor.
radar
  • radar
Did you choose D "did i get the right answer??:D"
anonymous
  • anonymous
no, thats a super smiley face, haha. i choose C and it was correct
radar
  • radar
O..K that is correct!
mathstudent55
  • mathstudent55
Applying the first rule we get: \( \Large \log_4 \dfrac{8}{x^2} = \log_4 8 - \log_4 x^2\) Applying the second rule we get: \( \Large \log_4 \dfrac{8}{x^2} = \log_4 8 - 2 \log_4 x\)
mathstudent55
  • mathstudent55
You are correct. Good job!
radar
  • radar
Sorry about that I guess I am not "hip" to internet speak lol.
radar
  • radar
I thought you were on track that is why I said you are doing fine, then you posted that and it threw me off.
radar
  • radar
@mathstudent55 Just a problem in "internet slang"

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