Help
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- Jravenv

Help
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- schrodinger

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- Jravenv

##### 1 Attachment

- anonymous

|dw:1433790548235:dw|

- anonymous

Maybe that can get you started!

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## More answers

- Jravenv

Can you help me break it down? the formatting of these just makes my brain shut down.

- anonymous

Well you have so many fractions so it's a good idea to start getting rid of those first. What I did in the picture is multiply the whole thing by (2/1)/(2/1) which is the same as multiplying it by 1.. which wouldn't change the values but it will get rid of the fractions!

- anonymous

So I decided to get rid of that 2 in the denominator, and in order to do that you need to multiply it by a 2

- Jravenv

So like top and bottom or just multiply it to leave the y

- anonymous

well lets look at the bottom first. (y/2) * (2/1) = 2y/2 = y

- anonymous

so maybe try multiplying out that equation I drew up there

- Jravenv

3+ 2/6y?

- anonymous

|dw:1433791054094:dw|

- anonymous

Not quite, keep in mind that you need to multiply that 2 by both terms!

- Jravenv

6+2/6y ?

- anonymous

yes but remember there is also the y/2 in the denominator

- Jravenv

So I put the y/2 under it

- Jravenv

What's the next step?

- anonymous

But you haven't multiplied the (2/1) by the (y/2) yet!

- Jravenv

2y/2?

- anonymous

Yup. and what would that simpify to?

- Jravenv

y

- anonymous

Great. So now write out the new the equation that we have.

- Jravenv

|dw:1433791502822:dw|

- anonymous

So try and clear that fraction on the top with the 6y using the same method I used to clear the bottom fraction.

- Jravenv

How do you mean?

- anonymous

Well everything we have done led us to getting rid of that fraction on the bottom (y/2) so now it just says y.
We want to do that same thing for the 2/(6y) in the denominator. How do you think we could get rid of the fraction?

- Jravenv

divide the 2/6y and the y?

- anonymous

Well remember if you do something like divide or multiply one of the terms, you need to do that same thing to EVERYTHING else in the equation, otherwise you would be changing it!

- Jravenv

so divide the denominator by the numerator?

- anonymous

I'm not quite sure what you mean.

- Jravenv

y by the top of the fraction?

- anonymous

We want to clear that fraction in the numerator. So we need to multiply the entire fraction by something that will clear that fraction.

- anonymous

what will get rid of the 6y in the 2/(6y)?

- Jravenv

multiply times 3?

- anonymous

|dw:1433791955899:dw|

- anonymous

You're almost there, but we still have a fraction left

- Jravenv

4?

- anonymous

What about 4?

- anonymous

That is a y if it is not clear in the drawing

- Jravenv

so would I multiply by 3y? I don't know I'm a little lost

- anonymous

Well try it out! |dw:1433792117437:dw|

- Jravenv

So it's 1? xD

- anonymous

Well that one term is.. which is good because it means we no longer have a bunch of fractions in the numerator and denominator.
Just remember if you multiply one term by something, you need to multiply everything else by that same thing. So do that now.

- Jravenv

I'm confused :/

- anonymous

I think it would help if you always write out the full equation so that you don't accidentally skip steps.

- anonymous

|dw:1433792424478:dw|

- anonymous

What are you going to multiply this by to clear that 2/6y fraction?

- anonymous

If the whole 'multiply all terms by the same thing' thing is confusing, think about it like this.
1 + 1 = 2
I can multiply everything in that by 3 to get
(1)(3) + (1)(3) = (2)(3)
3 + 3 = 6
Which is correct!
But I CANNOT just multiply one of the terms by 3 as you will see:
1 + 1 = 2
(1)(3) + 1 = 2
3 + 1 = 2
Well that's obviously wrong! So nee the apply this same thinking to the question we are dealing with.

- Jravenv

Ohh okay.

- anonymous

So you discovered that multiplying 2/6y by 3/y clears that fraction. You just need to remember to multiply everything in the equation by that as well otherwise you are changing the equation into something entirely new.

- Jravenv

Ahh, yeah. okay.

- anonymous

So do you know what step to do next?

- Jravenv

No, I feel so dumb.

- anonymous

Don't feel dumb. Honestly this stuff is very tricky to get. I am talking calculus 2 right now and SO many people struggle with this algebra stuff. You can even look in the calc section of this site and see that the main thing people are finding tough is the algebra!
It just takes time and a lot of practice.

- anonymous

|dw:1433793417267:dw| So this is where we are at now.

- Jravenv

What do I have to do?

- anonymous

Well multiplying out what I drew would be good.

- anonymous

Because you discovered that when you multiply it by 3y it will clear the fraction.

- Jravenv

so the top would be 18 + 1?

- anonymous

Sounds good but what about the entire equation?

- anonymous

Also I think you are missing a y in the numerator

- Jravenv

|dw:1433794021102:dw|

- anonymous

:)

- Jravenv

Thank you so much, you're sincerely the most helpful person that has come around, it might be a slow process but you didn't call me dumb or give up on me. I'm very thankful

- anonymous

No worries! Glad I could help.
The main thing to do with these questions is to see what you need to multiply the fractions by in order to clear them. Then once you have that figured out, multiply the WHOLE equation by that thing. Everything else will fall into place ^^

- Jravenv

Thank you :3 I'll remember that.

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