Jravenv
  • Jravenv
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Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Jravenv
  • Jravenv
anonymous
  • anonymous
|dw:1433790548235:dw|
anonymous
  • anonymous
Maybe that can get you started!

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Jravenv
  • Jravenv
Can you help me break it down? the formatting of these just makes my brain shut down.
anonymous
  • anonymous
Well you have so many fractions so it's a good idea to start getting rid of those first. What I did in the picture is multiply the whole thing by (2/1)/(2/1) which is the same as multiplying it by 1.. which wouldn't change the values but it will get rid of the fractions!
anonymous
  • anonymous
So I decided to get rid of that 2 in the denominator, and in order to do that you need to multiply it by a 2
Jravenv
  • Jravenv
So like top and bottom or just multiply it to leave the y
anonymous
  • anonymous
well lets look at the bottom first. (y/2) * (2/1) = 2y/2 = y
anonymous
  • anonymous
so maybe try multiplying out that equation I drew up there
Jravenv
  • Jravenv
3+ 2/6y?
anonymous
  • anonymous
|dw:1433791054094:dw|
anonymous
  • anonymous
Not quite, keep in mind that you need to multiply that 2 by both terms!
Jravenv
  • Jravenv
6+2/6y ?
anonymous
  • anonymous
yes but remember there is also the y/2 in the denominator
Jravenv
  • Jravenv
So I put the y/2 under it
Jravenv
  • Jravenv
What's the next step?
anonymous
  • anonymous
But you haven't multiplied the (2/1) by the (y/2) yet!
Jravenv
  • Jravenv
2y/2?
anonymous
  • anonymous
Yup. and what would that simpify to?
Jravenv
  • Jravenv
y
anonymous
  • anonymous
Great. So now write out the new the equation that we have.
Jravenv
  • Jravenv
|dw:1433791502822:dw|
anonymous
  • anonymous
So try and clear that fraction on the top with the 6y using the same method I used to clear the bottom fraction.
Jravenv
  • Jravenv
How do you mean?
anonymous
  • anonymous
Well everything we have done led us to getting rid of that fraction on the bottom (y/2) so now it just says y. We want to do that same thing for the 2/(6y) in the denominator. How do you think we could get rid of the fraction?
Jravenv
  • Jravenv
divide the 2/6y and the y?
anonymous
  • anonymous
Well remember if you do something like divide or multiply one of the terms, you need to do that same thing to EVERYTHING else in the equation, otherwise you would be changing it!
Jravenv
  • Jravenv
so divide the denominator by the numerator?
anonymous
  • anonymous
I'm not quite sure what you mean.
Jravenv
  • Jravenv
y by the top of the fraction?
anonymous
  • anonymous
We want to clear that fraction in the numerator. So we need to multiply the entire fraction by something that will clear that fraction.
anonymous
  • anonymous
what will get rid of the 6y in the 2/(6y)?
Jravenv
  • Jravenv
multiply times 3?
anonymous
  • anonymous
|dw:1433791955899:dw|
anonymous
  • anonymous
You're almost there, but we still have a fraction left
Jravenv
  • Jravenv
4?
anonymous
  • anonymous
What about 4?
anonymous
  • anonymous
That is a y if it is not clear in the drawing
Jravenv
  • Jravenv
so would I multiply by 3y? I don't know I'm a little lost
anonymous
  • anonymous
Well try it out! |dw:1433792117437:dw|
Jravenv
  • Jravenv
So it's 1? xD
anonymous
  • anonymous
Well that one term is.. which is good because it means we no longer have a bunch of fractions in the numerator and denominator. Just remember if you multiply one term by something, you need to multiply everything else by that same thing. So do that now.
Jravenv
  • Jravenv
I'm confused :/
anonymous
  • anonymous
I think it would help if you always write out the full equation so that you don't accidentally skip steps.
anonymous
  • anonymous
|dw:1433792424478:dw|
anonymous
  • anonymous
What are you going to multiply this by to clear that 2/6y fraction?
anonymous
  • anonymous
If the whole 'multiply all terms by the same thing' thing is confusing, think about it like this. 1 + 1 = 2 I can multiply everything in that by 3 to get (1)(3) + (1)(3) = (2)(3) 3 + 3 = 6 Which is correct! But I CANNOT just multiply one of the terms by 3 as you will see: 1 + 1 = 2 (1)(3) + 1 = 2 3 + 1 = 2 Well that's obviously wrong! So nee the apply this same thinking to the question we are dealing with.
Jravenv
  • Jravenv
Ohh okay.
anonymous
  • anonymous
So you discovered that multiplying 2/6y by 3/y clears that fraction. You just need to remember to multiply everything in the equation by that as well otherwise you are changing the equation into something entirely new.
Jravenv
  • Jravenv
Ahh, yeah. okay.
anonymous
  • anonymous
So do you know what step to do next?
Jravenv
  • Jravenv
No, I feel so dumb.
anonymous
  • anonymous
Don't feel dumb. Honestly this stuff is very tricky to get. I am talking calculus 2 right now and SO many people struggle with this algebra stuff. You can even look in the calc section of this site and see that the main thing people are finding tough is the algebra! It just takes time and a lot of practice.
anonymous
  • anonymous
|dw:1433793417267:dw| So this is where we are at now.
Jravenv
  • Jravenv
What do I have to do?
anonymous
  • anonymous
Well multiplying out what I drew would be good.
anonymous
  • anonymous
Because you discovered that when you multiply it by 3y it will clear the fraction.
Jravenv
  • Jravenv
so the top would be 18 + 1?
anonymous
  • anonymous
Sounds good but what about the entire equation?
anonymous
  • anonymous
Also I think you are missing a y in the numerator
Jravenv
  • Jravenv
|dw:1433794021102:dw|
anonymous
  • anonymous
:)
Jravenv
  • Jravenv
Thank you so much, you're sincerely the most helpful person that has come around, it might be a slow process but you didn't call me dumb or give up on me. I'm very thankful
anonymous
  • anonymous
No worries! Glad I could help. The main thing to do with these questions is to see what you need to multiply the fractions by in order to clear them. Then once you have that figured out, multiply the WHOLE equation by that thing. Everything else will fall into place ^^
Jravenv
  • Jravenv
Thank you :3 I'll remember that.

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