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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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this is what i get for graphing both, but the answers are confusing me.

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u don't need to graph the functions to determine the answer
okay. how can i determine the answer without graphing them?
\(\LARGE f(x)=2\log_{10}(x-1)-4 \) \(\LARGE g(x)=10(x-1)^2+4\) first I just want to put the functions up not to click a different tab every time
the parent logarithmic function is \(\LARGE L(x)=\log_{10}(x) \) (naming it L of x, becuase it is logarithmic) \(\LARGE L(x+a)=\log_{10}(x+a) \) is a shift a units to the left \(\LARGE L(x+a)=\log_{10}(x-a) \) is a shift a units to the right \(\LARGE L(x)=B\times \log_{10}(x) \) multiples times a scale factor B
how do you obtain the g(x) from a parent function \(\LARGE L(x)=\log_{10}(x) \) ?
i mean how do you obtain f(x) (not g of x)
When you replace x with x - h, h being a number, the function is translated h units horizontally. When you replace y with y - k, k being a number, the function is translated k units vertically.
so are you two saying that it's some sort of vertical shift?
someone please help me
can someone help me?
SOMEONE

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