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anonymous
 one year ago
A ball is dropped from the top of a tower 100m high simultaneously another ball is thorwn upward with a speed of 50 meter per second. After what time do they cross each other?
(a) 1s
(b) 2s
(c) 3s
(4) 4s
anonymous
 one year ago
A ball is dropped from the top of a tower 100m high simultaneously another ball is thorwn upward with a speed of 50 meter per second. After what time do they cross each other? (a) 1s (b) 2s (c) 3s (4) 4s

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When they cross each other they will have the same displacement. Set up equations for the displacements of each and equate them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but which equation, i've tried by appling S=vi t+1/2 at^2 but that does not work for me.Please can you solve it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are on the right track. For the ball dropped downward, vi = 0. So\[\color{green}{\vec{d} = \frac{1}{2}\vec{g}t^2 }\] Set up the other equation and equate the two and solve for t.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i've tried many methods but couldn't solve it,please solve it if you can

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.1Assume displacemt x and 100x for thrown and release one. Then 100x=0.5gt^2 x=1005t^2 Again For the thrown ball x=50t5t^2 As time for both balls are equal Equating both values you will get the answer 2.

shamim
 one year ago
Best ResponseYou've already chosen the best response.0We wanna help u. Response plz!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok,thanks i've got it
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