Pawanyadav
  • Pawanyadav
Lim{(x+x^-1)e^(1÷x)-x=? Where x tending to infinity.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
geerky42
  • geerky42
\[\lim_{x\to\infty} (x+x^{-1})e^{1/x}-x\]?
Pawanyadav
  • Pawanyadav
Ya this is the question. what's the solution?
welshfella
  • welshfella
Hint : as x approaches infinity 1/x approaches zero so e^1/x will approach 1.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

geerky42
  • geerky42
\[\lim_{x\to\infty} (x+x^{-1})e^{1/x}-x \\~\\= \lim_{x\to\infty} xe^{1/x}+x^{-1}e^{1/x}-x\\~\\ = \lim_{x\to\infty} x(e^{1/x}-1)+x^{-1}e^{1/x}\] Here, \(x^{-1}e^{1/x}\) approaches to 0. So we are left with \[\lim_{x\to\infty} x(e^{1/x}-1)\\~\\=\lim_{x\to\infty} \dfrac{e^{1/x}-1}{\dfrac{1}{x}}\]From here, use L'Hopital's Rule.
geerky42
  • geerky42
@Pawanyadav Does that help?
anonymous
  • anonymous
I don't think so because it's not the solution :P
Pawanyadav
  • Pawanyadav
Yes absolutly
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
geerky42
  • geerky42
Correct.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
geerky42
  • geerky42
|dw:1433801268065:dw|
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
Pawanyadav
  • Pawanyadav
The answer After solving is 1.
geerky42
  • geerky42
@Zarkon I think something is buggy.
geerky42
  • geerky42
I see so many replies "The answer After solving is 1."

Looking for something else?

Not the answer you are looking for? Search for more explanations.