anonymous
  • anonymous
The number of two-digit positive integers for which the units digit is not equal to the tens digit.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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misty1212
  • misty1212
HI!!
anonymous
  • anonymous
hi misty =)
misty1212
  • misty1212
my guess is \(81\) reason as follows: you have nine choices for the tens place digit (it cannot be zero) then another 9 choices for the ones place (it can be zero, but it cannot be the tens digit)

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More answers

misty1212
  • misty1212
by the counting principle you get \(9\times 9=81\)
anonymous
  • anonymous
ouuuuu niceeeee okay got it thanks!
misty1212
  • misty1212
course i could be wrong maybe @geerky42 has a different answer
anonymous
  • anonymous
it was right
geerky42
  • geerky42
There are \(99-10+1 = 90\) two digits numbers. Now exclude numbers where tens digit and unit digit are same; 11, 22, 33, 44, ..., 99 There are \(9\) of them. So you have \(90-9 = \boxed{81}\) So @misty1212 is correct.
anonymous
  • anonymous
hey why do u exclude the 11, 22,33,44 etc.?????
misty1212
  • misty1212
for which the units digit is not equal to the tens digit.
anonymous
  • anonymous
but doesnt that just mean 10, 20, 30, 40 etc?
geerky42
  • geerky42
No. "units digit is equal to the tens digit" means 11, 22, 33, etc. So here, we have "units digit is NOT equal to the tens digit", which means 10, 12, 13, ..., 20, 21, 23, ..., 31, 32, 34, ..., etc.
geerky42
  • geerky42
We counted ALL two digits numbers, then we un-counted number where "units digit is equal to the tens digit"

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