jewelotaku2001 one year ago Write the value of the expression. 2^3/2^3 A. 0 B. 1 C. 2 D. 3 4^7/4^9 A. -16 B. 1/16 C. 1/8 D. 8

1. anonymous

What do you think the answer is to both? :)

2. anonymous

We can work with your understanding from there :)

3. jewelotaku2001

A and D?

4. anonymous

|dw:1433800005478:dw|

5. anonymous

Hmm.. close but not yet

6. anonymous

What is 12/12?

7. jewelotaku2001

B and D?

8. anonymous

For number 1 B is correct… 12/12 = 1 2^3/2^3 = 1

9. anonymous

Do you understand where it came from though?

10. jewelotaku2001

Yes... but I have no idea about the second one...

11. anonymous

Let me draw this out for you to increase your understanding :)

12. Nnesha

12 ?? 2 ^3 can be written as 2 time 2 times 2 =8

13. anonymous

What is 4^7 = ?

14. jewelotaku2001

16,384

15. anonymous

@Nnesha it was an example :)

16. anonymous

Now was does 4^9 = ?

17. jewelotaku2001

262,144

18. anonymous

Now.. we have really big numbers so you can also simplify the numbers before digging deeper.

19. Nnesha

0hhh great but we don't need a calculator for this one easy wat to solve this apply exponent rules $\huge\rm \frac{ x^m }{ x^n } =x^{m-n}$

20. Nnesha

way*

21. anonymous

There are multiple ways to do this ^

22. anonymous

That is the Power of A Quotient exponent property :)

23. Nnesha

yep :-) but if we solve it without calculator then we have to apply exponent rules :-)

24. jewelotaku2001

The exponent rule wouldn't work for this equation though, with my answer options. 7 - 9 doesn't equal any of my answers choices...

25. anonymous

|dw:1433800389103:dw|

26. Nnesha

remember if there is a negative sign you have to flip it $\huge\rm x^{-m} = \frac{ 1 }{ x^m }$ this unit is all abt exponent rules :-)

27. jewelotaku2001

OH

28. Nnesha

$\huge\rm \frac{ x^{-m} }{ 1} = \frac{ 1 }{ x^m }$ and $\huge\rm \frac{ 1 }{ x^{-m}} = x^m$ gO_Od luck!

29. jewelotaku2001

@Aureyliant and @Nnesha thanks :-)

30. anonymous

You're welcome. :)

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