jewelotaku2001
  • jewelotaku2001
Write the value of the expression. 2^3/2^3 A. 0 B. 1 C. 2 D. 3 4^7/4^9 A. -16 B. 1/16 C. 1/8 D. 8
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
What do you think the answer is to both? :)
anonymous
  • anonymous
We can work with your understanding from there :)
jewelotaku2001
  • jewelotaku2001
A and D?

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More answers

anonymous
  • anonymous
|dw:1433800005478:dw|
anonymous
  • anonymous
Hmm.. close but not yet
anonymous
  • anonymous
What is 12/12?
jewelotaku2001
  • jewelotaku2001
B and D?
anonymous
  • anonymous
For number 1 B is correct… 12/12 = 1 2^3/2^3 = 1
anonymous
  • anonymous
Do you understand where it came from though?
jewelotaku2001
  • jewelotaku2001
Yes... but I have no idea about the second one...
anonymous
  • anonymous
Let me draw this out for you to increase your understanding :)
Nnesha
  • Nnesha
12 ?? 2 ^3 can be written as 2 time 2 times 2 =8
anonymous
  • anonymous
What is 4^7 = ?
jewelotaku2001
  • jewelotaku2001
16,384
anonymous
  • anonymous
@Nnesha it was an example :)
anonymous
  • anonymous
Now was does 4^9 = ?
jewelotaku2001
  • jewelotaku2001
262,144
anonymous
  • anonymous
Now.. we have really big numbers so you can also simplify the numbers before digging deeper.
Nnesha
  • Nnesha
0hhh great but we don't need a calculator for this one easy wat to solve this apply exponent rules \[\huge\rm \frac{ x^m }{ x^n } =x^{m-n}\]
Nnesha
  • Nnesha
way*
anonymous
  • anonymous
There are multiple ways to do this ^
anonymous
  • anonymous
That is the Power of A Quotient exponent property :)
Nnesha
  • Nnesha
yep :-) but if we solve it without calculator then we have to apply exponent rules :-)
jewelotaku2001
  • jewelotaku2001
The exponent rule wouldn't work for this equation though, with my answer options. 7 - 9 doesn't equal any of my answers choices...
anonymous
  • anonymous
|dw:1433800389103:dw|
Nnesha
  • Nnesha
remember if there is a negative sign you have to flip it \[\huge\rm x^{-m} = \frac{ 1 }{ x^m }\] this unit is all abt exponent rules :-)
jewelotaku2001
  • jewelotaku2001
OH
Nnesha
  • Nnesha
\[\huge\rm \frac{ x^{-m} }{ 1} = \frac{ 1 }{ x^m }\] and \[\huge\rm \frac{ 1 }{ x^{-m}} = x^m\] gO_Od luck!
jewelotaku2001
  • jewelotaku2001
@Aureyliant and @Nnesha thanks :-)
anonymous
  • anonymous
You're welcome. :)

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