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anonymous
 one year ago
Quadrilateral OPQR is inscribed inside a circle as shown below. What equation would be needed to solve for angle Q? What is the measure of angle Q? You must show all work and calculations to receive credit.
anonymous
 one year ago
Quadrilateral OPQR is inscribed inside a circle as shown below. What equation would be needed to solve for angle Q? What is the measure of angle Q? You must show all work and calculations to receive credit.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@kropot72 @KendrickLamar2014 @Nnesha @IrishBoy123 @mathstudent55 @MikeyMaximum @Compassionate help explain it in steps?

jabez177
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 @pooja195 @geerky42 This is a bit too hard.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1For ANY quadrilateral inscribled inside a circle, sum of opposite angles is always \(180^\text o\).

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1\[m\angle R+m\angle P=180^\text o\]\[m\angle O+m\angle Q=180^\text o\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does that mean M<Q=180*?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1No, not necessary. We know that sum of angle O and Q is 180. So we have \((2x) + (2x+4) = 180\) Same goes to angle P and R.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how do I find the measure of angle Q? (2x)+(2x+4)=180 do I do this?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1First by solve for x.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1after that, plug in x to find measure of angle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait I read my own question wrong. I just need to find the equation that would be needed to solve for angle Q

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for all the help I think I understand now!
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