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anonymous

  • one year ago

Quadrilateral OPQR is inscribed inside a circle as shown below. What equation would be needed to solve for angle Q? What is the measure of angle Q? You must show all work and calculations to receive credit.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @kropot72 @KendrickLamar2014 @Nnesha @IrishBoy123 @mathstudent55 @MikeyMaximum @Compassionate help explain it in steps?

  3. anonymous
    • one year ago
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    @jabez177

  4. jabez177
    • one year ago
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    @mathstudent55 @pooja195 @geerky42 This is a bit too hard.

  5. geerky42
    • one year ago
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    For ANY quadrilateral inscribled inside a circle, sum of opposite angles is always \(180^\text o\).

  6. geerky42
    • one year ago
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    \[m\angle R+m\angle P=180^\text o\]\[m\angle O+m\angle Q=180^\text o\]

  7. anonymous
    • one year ago
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    does that mean M<Q=180*?

  8. anonymous
    • one year ago
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    90*

  9. geerky42
    • one year ago
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    No, not necessary. We know that sum of angle O and Q is 180. So we have \((2x) + (2x+4) = 180\) Same goes to angle P and R.

  10. anonymous
    • one year ago
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    so how do I find the measure of angle Q? (2x)+(2x+4)=180 do I do this?

  11. geerky42
    • one year ago
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    First by solve for x.

  12. geerky42
    • one year ago
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    after that, plug in x to find measure of angle.

  13. anonymous
    • one year ago
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    Oh wait I read my own question wrong. I just need to find the equation that would be needed to solve for angle Q

  14. anonymous
    • one year ago
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    Thank you for all the help I think I understand now!

  15. geerky42
    • one year ago
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    Ok no problem

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