help_people
  • help_people
Hi this question I am not sure about, I am debating so may you please help me confirm the correct answer (Algebra)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
help_people
  • help_people
The table below shows four systems of equations: System 1 System 2 System 3 System 4 4x − 5y = 2 3x − y = 8 4x − 5y = 2 10x − 7y = 18 4x − 5y = 2 3x − 8y = 4 4x − 5y = 2 10x + 3y = 15 Which pair of systems will have the same solution? System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to two times the second equation in system 1 System 2 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 2 to two times the second equation in system 2 System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to three times the second equation in system 1 System 2 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 2 to three times the second equation in system 2
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  • help_people
|dw:1433801513354:dw|

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help_people
  • help_people
@Nnesha
anonymous
  • anonymous
15
help_people
  • help_people
? @0404diego
anonymous
  • anonymous
hi
help_people
  • help_people
@mathstudent55
help_people
  • help_people
hi 04
help_people
  • help_people
i am not sure may you walk me through the process?
help_people
  • help_people
@perl
mathstudent55
  • mathstudent55
Every system has the same equation: 4x - 5y = 2
mathstudent55
  • mathstudent55
We need to look at the second equation of the 4 systems and compare them.
mathstudent55
  • mathstudent55
4x − 5y = 2 3x − y = 8 4x − 5y = 2 10x − 7y = 18 4x − 5y = 2 3x − 8y = 4 4x − 5y = 2 10x + 3y = 15
help_people
  • help_people
well that have 10 x and 3x?
help_people
  • help_people
but all different ys?
mathstudent55
  • mathstudent55
Look at choice A. Choice A tells you that the second equation of the second system is 2 times the second equation of the first system added to the first equation of the first system. If this is true, the equations are the same equation and the solutions will be the same. All you need to do is see if this is true. Multiply the second eq. of system 1 by 2. Then add it to the first eq. of system 1. What do you get?
help_people
  • help_people
who do i do that
help_people
  • help_people
like 12-6y=16
mathstudent55
  • mathstudent55
Here is eq. 2 of system 1: 3x − y = 8 Multiply both sides of the equation by 2. What do you get?
mathstudent55
  • mathstudent55
Multiply both sides by 2: 2(3x − y) = 2(8) What do you get?
help_people
  • help_people
6x-2y=16
mathstudent55
  • mathstudent55
Great. Now add it to the first eq. of system 1. 4x - 5y = 2 (+) 6x - 2y =16 ----------------- What do you get?
help_people
  • help_people
10x+7y=18 @mathstudent55
mathstudent55
  • mathstudent55
Check the +7y. Notice you are adding -5y and -2y. What is -5y + (-2y) = ?
help_people
  • help_people
-7y
mathstudent55
  • mathstudent55
-5y + (-2y) = -5y - 2y = -7y Correct.
mathstudent55
  • mathstudent55
The equation is: 10x - 7y = 18 Now compare this new equation with the second eq. of system, 2.
help_people
  • help_people
ok so what would i do? can you walk me through with it? @mathstudent55
mathstudent55
  • mathstudent55
The equation you got by doing what choice A tells you is exactly the second eq. of system 2. That means the answer is choice A. The first and second systems have the same answer.
help_people
  • help_people
thank you so much may you help me w. more (its about squre roots)
mathstudent55
  • mathstudent55
Sorry, but I have to go.
mathstudent55
  • mathstudent55
You're welcome.

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