- anonymous

quick question.... On a xy-coordinate how do i know what to plug in the y2-y1/x2-x1 formula

- jamiebookeater

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- idku

u should know the 2 points through which your line is going
or one x or y coordinate can be not given, but then you have to know the slope to solve for this coordinate

- anonymous

if the y-intercept is 12 and the x-intercept is 5 ... how do i know which one to plug in where?

- Nnesha

y = mx + b
where m is slope and b is y-intercept
x-intercept is when y =0 so you can write it in parentheses (x,y)----->>(5,0)

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## More answers

- anonymous

no but in the y2-y1/x2/x1

- Nnesha

ohh so if y-intercept is 12
remember y-intercept when line cross y-axis when x=0
so (0 ,12)
and x-intercept like i say x when line cross x-axis when y = 0
so (5,0)

- anonymous

yea so how do i know which goes first in the y2-y1/x2-x1

- Nnesha

|dw:1433802336037:dw|
and it doesn't matter
just remember y values should be at the top

- anonymous

so it doesn't mater if the 12 is y2 or y1 in the equation? and the same for the 5 ?

- Nnesha

yes right :-)

- anonymous

oh.... hmmmmm well lemme try my question because i got something different...

- anonymous

wait no it's not it....

- anonymous

i'm supposed to get a -12/5 but if i plug it in anywhere i can also get a positive 12/5

- Nnesha

or you can see which number is coming first for exxample
(5,0)(0,12)|dw:1433802577923:dw|
(0,12) is first so y_1 is 12 that's how i do it

- anonymous

so left to right whatever is first? so it would be 12-0/ 0-5?

- Nnesha

it doesn't matter you will get the same answer :-)

- anonymous

ohhh okay so always right to left?

- Nnesha

yep that works too

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @yomamabf
i'm supposed to get a -12/5 but if i plug it in anywhere i can also get a positive 12/5
\(\color{blue}{\text{End of Quote}}\)
(5,0)(0,12)
\[\huge\rm \frac{ 12-0 }{ 0-5 }=-\frac{ 12 }{ 5 }\]
now other way
(0,12)(5,0)
\[\frac{ 0-12 }{ 5-0} = \frac{ -12 }{ 5 }\]
same ?

- anonymous

oh okay i got it

- Nnesha

u will get the same answer
:-)

- anonymous

also it can be this too right? y=m(5)+12
=-12/5

- Nnesha

nope
x_2 - x_1 = 5 in this case bec x = 0 so that will work
but NO!

- Nnesha

Let x_2 = 3 and x_1 = 1
x_2 - x_1 = 2-1 =1
so you CAN'T substitute 1 for just x

- anonymous

hmmm okay

- Nnesha

yeah :-)

- anonymous

thank you <333

- Nnesha

but you can pick any x value from two order pair (5,0)(0,12)
to plug in this equation y = mx+b
u will get the same answer

- Nnesha

my pleasure :-)
gO_Od luck!

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