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anonymous

  • one year ago

quick question.... On a xy-coordinate how do i know what to plug in the y2-y1/x2-x1 formula

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  1. idku
    • one year ago
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    u should know the 2 points through which your line is going or one x or y coordinate can be not given, but then you have to know the slope to solve for this coordinate

  2. anonymous
    • one year ago
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    if the y-intercept is 12 and the x-intercept is 5 ... how do i know which one to plug in where?

  3. Nnesha
    • one year ago
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    y = mx + b where m is slope and b is y-intercept x-intercept is when y =0 so you can write it in parentheses (x,y)----->>(5,0)

  4. anonymous
    • one year ago
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    no but in the y2-y1/x2/x1

  5. Nnesha
    • one year ago
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    ohh so if y-intercept is 12 remember y-intercept when line cross y-axis when x=0 so (0 ,12) and x-intercept like i say x when line cross x-axis when y = 0 so (5,0)

  6. anonymous
    • one year ago
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    yea so how do i know which goes first in the y2-y1/x2-x1

  7. Nnesha
    • one year ago
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    |dw:1433802336037:dw| and it doesn't matter just remember y values should be at the top

  8. anonymous
    • one year ago
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    so it doesn't mater if the 12 is y2 or y1 in the equation? and the same for the 5 ?

  9. Nnesha
    • one year ago
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    yes right :-)

  10. anonymous
    • one year ago
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    oh.... hmmmmm well lemme try my question because i got something different...

  11. anonymous
    • one year ago
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    wait no it's not it....

  12. anonymous
    • one year ago
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    i'm supposed to get a -12/5 but if i plug it in anywhere i can also get a positive 12/5

  13. Nnesha
    • one year ago
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    or you can see which number is coming first for exxample (5,0)(0,12)|dw:1433802577923:dw| (0,12) is first so y_1 is 12 that's how i do it

  14. anonymous
    • one year ago
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    so left to right whatever is first? so it would be 12-0/ 0-5?

  15. Nnesha
    • one year ago
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    it doesn't matter you will get the same answer :-)

  16. anonymous
    • one year ago
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    ohhh okay so always right to left?

  17. Nnesha
    • one year ago
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    yep that works too

  18. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @yomamabf i'm supposed to get a -12/5 but if i plug it in anywhere i can also get a positive 12/5 \(\color{blue}{\text{End of Quote}}\) (5,0)(0,12) \[\huge\rm \frac{ 12-0 }{ 0-5 }=-\frac{ 12 }{ 5 }\] now other way (0,12)(5,0) \[\frac{ 0-12 }{ 5-0} = \frac{ -12 }{ 5 }\] same ?

  19. anonymous
    • one year ago
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    oh okay i got it

  20. Nnesha
    • one year ago
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    u will get the same answer :-)

  21. anonymous
    • one year ago
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    also it can be this too right? y=m(5)+12 =-12/5

  22. Nnesha
    • one year ago
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    nope x_2 - x_1 = 5 in this case bec x = 0 so that will work but NO!

  23. Nnesha
    • one year ago
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    Let x_2 = 3 and x_1 = 1 x_2 - x_1 = 2-1 =1 so you CAN'T substitute 1 for just x

  24. anonymous
    • one year ago
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    hmmm okay

  25. Nnesha
    • one year ago
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    yeah :-)

  26. anonymous
    • one year ago
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    thank you <333

  27. Nnesha
    • one year ago
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    but you can pick any x value from two order pair (5,0)(0,12) to plug in this equation y = mx+b u will get the same answer

  28. Nnesha
    • one year ago
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    my pleasure :-) gO_Od luck!

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