anonymous
  • anonymous
A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 5y + 9z = 1 Which of the following is a possible step used in eliminating the y-term? (y + z = 6) ⋅ 9 (y + z = 6) ⋅ −5 (5y + 9z = 1) ⋅ 9 (5y + 9z = 1) ⋅ 5
Mathematics
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anonymous
  • anonymous
A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 5y + 9z = 1 Which of the following is a possible step used in eliminating the y-term? (y + z = 6) ⋅ 9 (y + z = 6) ⋅ −5 (5y + 9z = 1) ⋅ 9 (5y + 9z = 1) ⋅ 5
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
please help me
anonymous
  • anonymous
i gave you a medal

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geerky42
  • geerky42
You want to eliminate y terms, so you would want coefficient of y to be same, so you can just subtract equations there, right?
anonymous
  • anonymous
I was thinking B or C
anonymous
  • anonymous
alisurfcat i gave you a medal
geerky42
  • geerky42
So for first equation, coefficient of y is 1. In second equation, it is 5. So you want to multiply first equation by 5 so you can subtract. (Or -5 then add)
geerky42
  • geerky42
Right?
anonymous
  • anonymous
she right
anonymous
  • anonymous
I think so, so it will be B?
anonymous
  • anonymous
yes
anonymous
  • anonymous
thanks
anonymous
  • anonymous
your welcome

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