Jravenv
  • Jravenv
In how many ways can a gymnastics team of 4 be chosen from 9 gymnasts? 36 126 3,024
Mathematics
chestercat
  • chestercat
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sdfgsdfgs
  • sdfgsdfgs
1st team memeber - how many choices of gymnastics u get?
Jravenv
  • Jravenv
Idk :/
sdfgsdfgs
  • sdfgsdfgs
9 right?

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Jravenv
  • Jravenv
Yeah
sdfgsdfgs
  • sdfgsdfgs
second member? how much choices are left?
Jravenv
  • Jravenv
8?
sdfgsdfgs
  • sdfgsdfgs
Correct :) so for 4 members, it would be 9x8x7x6 BUT.....
Jravenv
  • Jravenv
it would be 3024
sdfgsdfgs
  • sdfgsdfgs
Let's say the team selected is A,B,C,D....does it make any difference whether it is ABCD or DCBA?
sdfgsdfgs
  • sdfgsdfgs
Now...remember i said BUT :P 3024 is too many because you are double counting ABCD and DCBA - that should be counted as 1
Jravenv
  • Jravenv
OHhhhhhh
sdfgsdfgs
  • sdfgsdfgs
It is Combination and you have to divide by 4x3x2x1 to get the right answer. The general eqn is: nCr = n!/r!(n - r)!

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