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Jravenv

  • one year ago

In how many ways can a gymnastics team of 4 be chosen from 9 gymnasts? 36 126 3,024

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  1. sdfgsdfgs
    • one year ago
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    1st team memeber - how many choices of gymnastics u get?

  2. Jravenv
    • one year ago
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    Idk :/

  3. sdfgsdfgs
    • one year ago
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    9 right?

  4. Jravenv
    • one year ago
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    Yeah

  5. sdfgsdfgs
    • one year ago
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    second member? how much choices are left?

  6. Jravenv
    • one year ago
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    8?

  7. sdfgsdfgs
    • one year ago
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    Correct :) so for 4 members, it would be 9x8x7x6 BUT.....

  8. Jravenv
    • one year ago
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    it would be 3024

  9. sdfgsdfgs
    • one year ago
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    Let's say the team selected is A,B,C,D....does it make any difference whether it is ABCD or DCBA?

  10. sdfgsdfgs
    • one year ago
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    Now...remember i said BUT :P 3024 is too many because you are double counting ABCD and DCBA - that should be counted as 1

  11. Jravenv
    • one year ago
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    OHhhhhhh

  12. sdfgsdfgs
    • one year ago
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    It is Combination and you have to divide by 4x3x2x1 to get the right answer. The general eqn is: nCr = n!/r!(n - r)!

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