A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
cosx/ (1+sinx) + (1+sinx)/ cosx= 2secx
anonymous
 one year ago
cosx/ (1+sinx) + (1+sinx)/ cosx= 2secx

This Question is Open

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \frac{cos(x)}{1 + sin(x)} + \frac{1 + sin(x)}{cos(x)} = 2sec(x)\] We need a common denominator first...what would that be?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1We can see the first fraction is missing a factor of cos(x) on the bottom...and we can see that the second fraction is missing a factor of 1 + sin(x) so we can work with that... \[\large \frac{cos(x)}{cos(x)} \times \frac{cos(x)}{1 + sin(x)} + \frac{1 + sin(x)}{1 + sin(x)} \times \frac{1 + sin(x)}{cos(x)} = 2sec(x)\] And simplify that down a bit \[\large \frac{cos^2(x)}{(1 + sin(x))cos(x)} + \frac{(1 + sin(x))^2}{(1 + sin(x))cos(x)} = 2sec(x)\] Now lets put them over the common denominator \[\large \frac{cos^2(x) + (1 + sin(x))^2}{(1 + sin(x))cos(x)} = 2sec(x)\] Now...what can we replace \(\large cos^2(x)\) with?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.