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anonymous

  • one year ago

A sample space S consists of five simple events with these probabilities: P(E1) = P(E2) = 0.15 P(E3) = 0.4 P(E4) = 2P(E5) a) Find the probabilities for simple events E4 and E5. How do I do this?

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  1. jim_thompson5910
    • one year ago
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    let x = P(E5) so P(E4) = 2*P(E5) = 2*x

  2. jim_thompson5910
    • one year ago
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    for this distribution to be a true probability distribution, all of the probabilities must add to 1 P(E1) + P(E2) + .... + P(E5) = 1

  3. anonymous
    • one year ago
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    right but how do i fugure the probability out from x?

  4. jim_thompson5910
    • one year ago
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    P(E1) + P(E2) + P(E3) + P(E4) + P(E5) = 1 0.15+0.15+0.4+2x+x = 1 solve for x

  5. anonymous
    • one year ago
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    x = 0.10?

  6. jim_thompson5910
    • one year ago
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    once you find x, you'll know P(E5) double x to get P(E4)

  7. jim_thompson5910
    • one year ago
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    x = 0.10 is correct

  8. anonymous
    • one year ago
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    Thank you Jim :)

  9. jim_thompson5910
    • one year ago
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    np

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