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anonymous

  • one year ago

Rates and Speed Calculas question

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I don't know how do get the equation; I know that i will need to take the derivative of that equation etc though. Thank you!

  3. anonymous
    • one year ago
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    Sorry i'm with another question. I will look at this when i return.

  4. IrishBoy123
    • one year ago
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    i think you need to start by connecting up mpg and mph. you have two different regions, with 40mph <=> 18mpg as the mid point |dw:1433935829387:dw| you should be able to get to \(mpg = -\frac{mph}{10} + 22\) and \(mpg = -\frac{mph}{5} + 26\) for mph's < and > 40mph. you can then get a volume usage "gallon/hour" number if you divide mpg by mph which you can then add that to the constant 4g/h leakage due to the hole in tank to get total \(\frac{dV}{dt}\) . this combined \(\frac{dV}{dt}\) you can integrate with initial value V(0) = 14 to arrive at V(t). the thing will stop when \(V(t_{final}) = 0\) so solve for \(t = t_{final}\) giving an expression terms of \(\dot x\), where \(\dot x\) is mph. by then it will have travelled \(\dot x \times t_{final}\); so you have an expression for distance in terms of \(\dot x\) which you can differentiate and solve to optimise \(\dot x\) . it's ugly.

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