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anonymous

  • one year ago

FAN AND MEDAL TO WHOEVER CAN HELP ME I need someone to work through this with me and explain it. A right triangle has base (x - 5) units and height (4x - 10) units. Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points) Part B: What is the area of the triangle? (3 points) Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials. (3 points)

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  1. anonymous
    • one year ago
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    me

  2. anonymous
    • one year ago
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    |dw:1433809231852:dw| A . you can get the hypotenuse using the pytagorean theorem: \[H^2=h^2+b^2\] B . the area can be found as: \[Area=\frac{b\times h}{2}\] start with those 2, using the expressions for b and h as a function of x

  3. anonymous
    • one year ago
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    17x2-90x+125

  4. anonymous
    • one year ago
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    okay.

  5. anonymous
    • one year ago
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    Not really. c is just (x-5). So c^2 is (x-5)^2 b is (4x-10) so b^2 is (4x-10)^2

  6. anonymous
    • one year ago
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    So for the area I would use the squared expressions in the formula or the original?

  7. anonymous
    • one year ago
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    the original

  8. anonymous
    • one year ago
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    okay

  9. anonymous
    • one year ago
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    I am in Algebra I so I haven't taken Geometry yet so I am kinda confused but my teacher gave me this question and I haven't learned how to do this..

  10. anonymous
    • one year ago
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    ok

  11. anonymous
    • one year ago
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    for the area you need to use the originals

  12. anonymous
    • one year ago
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    I'm going to get my sister to help me but thank you!!

  13. anonymous
    • one year ago
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    ok, just ask here if you need any more help...

  14. anonymous
    • one year ago
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    @Greg_D my sister wasn't very much help can you still help me?

  15. anonymous
    • one year ago
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    ill help

  16. anonymous
    • one year ago
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    okay

  17. anonymous
    • one year ago
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    what is the question

  18. anonymous
    • one year ago
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    the same one^

  19. anonymous
    • one year ago
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    ok

  20. anonymous
    • one year ago
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    @loveemmmma how far did you get with what @Greg_D suggested?

  21. anonymous
    • one year ago
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    I got the \[17x ^{2}-90x+125\] = H^2

  22. anonymous
    • one year ago
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    ok. so for the area multiply the base and height, then multiply by ½. \[A=\frac{ 1 }{ 2 }(x-5)(4x-10)\] Do you know FOIL?

  23. anonymous
    • one year ago
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    yeah

  24. anonymous
    • one year ago
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    OK. use it to multiply

  25. anonymous
    • one year ago
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    sorry, i was away from the computer, i see everything goes fine anyway :)

  26. anonymous
    • one year ago
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    I'm not sure but I think it might be \[12x ^{2}-5x+25\] I'm really bad at math.. :/

  27. anonymous
    • one year ago
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    @peachpi @Greg_D is this right??^

  28. anonymous
    • one year ago
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    |dw:1433812321296:dw| Divide by 2 to get 2x²-15x+25

  29. anonymous
    • one year ago
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    oh okay I see what you did.

  30. anonymous
    • one year ago
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    So that would be the area of the triangle right?

  31. anonymous
    • one year ago
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    @peachpi ? ^

  32. anonymous
    • one year ago
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    yes! that would be the area expressed as function of x

  33. anonymous
    • one year ago
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    amazing explanation @peachpi !!

  34. anonymous
    • one year ago
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    Okay. But I still need help with part A...

  35. anonymous
    • one year ago
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    @peachpi @Greg_D part A?

  36. anonymous
    • one year ago
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    Part A: What is the square of the length of the hypotenuse of the triangle? Show your work. (4 points)

  37. anonymous
    • one year ago
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    @Greg_D

  38. anonymous
    • one year ago
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    So what would I do with \[17x ^{2}-90x+125\] that we came up with earlier?

  39. anonymous
    • one year ago
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    sorry, im not at the computer all the time ... i took a look at the entire post.. that H^2 was the answer for part A.. is done!

  40. anonymous
    • one year ago
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    Oh so that is the answer I just leave it like that. and its okay!

  41. anonymous
    • one year ago
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    yes, that is...

  42. anonymous
    • one year ago
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    Alright then I think I can answer part C by myself. Thank you so much @Greg_D and @peachpi for your time, patience, and help it means a lot!!

  43. anonymous
    • one year ago
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    i know you can! you made an excellent work with parts A and B keep it up!

  44. anonymous
    • one year ago
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    Thank you!!

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