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bry856
 one year ago
The roots of an equation are x = 1 ± i.
The equation is x^2 + _____ + 2 = 0.
bry856
 one year ago
The roots of an equation are x = 1 ± i. The equation is x^2 + _____ + 2 = 0.

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sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.0"The roots of an equation are x = 1 ± i. " so the eqn is (x(1+i))*(x(1i)) = 0 expend the above n simply...what will u get?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0Let p and q be the roots of \(\Large x^2 + bx + c = 0\) Rule: \(\Large p+q = b\) so \(\Large b = (p+q)\)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well if you think about the general quadratic formula \[x = \frac{b \pm \sqrt{b^2  4ac}}{2a}\] you can see from the equation a = 1 and c = 2 so \[x = \frac{b \pm \sqrt{b^2  4 \times 1 \times 2}}{2 \times 1}\] then comparing the parts \[1 = \frac{b}{2}\] solve for b... and then check with b by using the rest of the quadratic formula \[b^2  8 = \frac{\sqrt{4i^2}}{2}\]
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