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Barrelracing

  • one year ago

suppose y varies directly with x. write a direct variation equation the relates x and y. then find the value of y when x =16 y=5 when x=2

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  1. rishavraj
    • one year ago
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    For direct variation y = kx k is the propotionality constany

  2. Barrelracing
    • one year ago
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    @bry856

  3. jim_thompson5910
    • one year ago
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    y = k*x y = k*2 ... replace x with 2 5 = k*2 ... replace y with 5 solve for k to get k = _________ (fill in the blank)

  4. rishavraj
    • one year ago
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    After getting k ...plug the value of k and x in the equation and get y

  5. Barrelracing
    • one year ago
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    y=40

  6. jim_thompson5910
    • one year ago
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    you should have found that k = 2.5 y = 2.5x when x = 16, y = 2.5*16 = 40 so you have the correct y value

  7. Barrelracing
    • one year ago
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    how do I find the direct variation that related x and y?

  8. jim_thompson5910
    • one year ago
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    what do you mean?

  9. Barrelracing
    • one year ago
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    it says write a direct variation equation that relates x and y. this is still the same problem.

  10. jim_thompson5910
    • one year ago
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    so it just wants the equation with x and y in it

  11. jim_thompson5910
    • one year ago
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    the k will be replaced with the numeric value you found

  12. Barrelracing
    • one year ago
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    so y=40x?

  13. jim_thompson5910
    • one year ago
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    So you can either say \[\Large y = \frac{5}{2}x\] or \[\Large y = 2.5x\]

  14. jim_thompson5910
    • one year ago
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    I started with y = kx then replaced k with 5/2 or 2.5

  15. Barrelracing
    • one year ago
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    ohh ok I get it now thank you

  16. jim_thompson5910
    • one year ago
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    np

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