At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
is the question asking if they are perpendicular to each other?
@greg_d all it is asking is if it is "normal"
I can't determine what or why or how it would be considered normal.. the rest of the homework was working on matrices
if the question is, are they "normal" (as perpendicular) to each other, you can use the dot product...
This is honestly the last problem and i don't know how i could do that..
ok, IF that is the question, we need to multiply them using the dot product. \[a.b=a_xb_x+a_yb_y\] since\[a.b=|a||b|cos(\theta) \] with theta beign the angle between the vectors. if that product is 0, said angle is 90º and they are indeed "normal" to each other
could you possibly solve that for me so i can use it next time i see something like this?
Similar Example: Let's say you had the two vectors u = <1,2> v = <5,7> The dot product of u and v is u dot v = 1*5 + 2*7 = 5 + 14 = 19 Since the dot product is not 0, this means that u and v are not perpendicular
@jim_thompson5910 @greg_d Thank you!!
:D that examples will lead you to the answer !