## anonymous one year ago Complete the square. -16t^2 - 8t = 10 Thanks!! :)

1. Astrophysics

Start off by moving the 10 to the left side, to complete the square , say we have $ax^2+bx+c = 0$ we do the following $x^2+2 \frac{ a }{ 2 }x+ \left( \frac{ a }{ 2 } \right)^2-\left( \frac{ a }{ 2 } \right)^2$

2. anonymous

Ok, what next?

3. anonymous

So far we have 16t2+8t+10=0 ?

4. anonymous

K I have to go...this is taking too long. Thanks

5. anonymous

Thanks but I just can't handle waiting for someone on a third-world internet connection

6. anonymous

I love explanations when they don't take 30 minutes