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anonymous

  • one year ago

Complete the square. -16t^2 - 8t = 10 Thanks!! :)

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  1. Astrophysics
    • one year ago
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    Start off by moving the 10 to the left side, to complete the square , say we have \[ax^2+bx+c = 0\] we do the following \[x^2+2 \frac{ a }{ 2 }x+ \left( \frac{ a }{ 2 } \right)^2-\left( \frac{ a }{ 2 } \right)^2\]

  2. anonymous
    • one year ago
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    Ok, what next?

  3. anonymous
    • one year ago
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    So far we have 16t2+8t+10=0 ?

  4. anonymous
    • one year ago
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    K I have to go...this is taking too long. Thanks

  5. anonymous
    • one year ago
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    Thanks but I just can't handle waiting for someone on a third-world internet connection

  6. anonymous
    • one year ago
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    I love explanations when they don't take 30 minutes

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spraguer (Moderator)
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