## jewelotaku2001 one year ago A radio signal travels at 3.00 times 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the Earth's surface if the satellite is orbiting at a height of 3.54 times 10^7 meters? Please help me with this. I'm not good at Scientific Notation...

1. jewelotaku2001

The following are the equations written:

2. jewelotaku2001

$3.00 \times 10^8$ $3.54 \times 10^7$

3. DDCamp

To find the time elapsed, you can use the equation: $time = distance / speed$

4. jewelotaku2001

So, would that be 1.15 seconds?

5. DDCamp

Working with scientific notation can be tricky at first, but it does make things easier in the long run. Each number in scientific notation has two parts, the base number and the part with the exponent, and you have to make sure you use the entire number in your calculations.

6. jewelotaku2001

The first notation is 30,000,000 and the second one is 35,400,000. I've already calculated what they were.

7. DDCamp

The nice part is this: You can find the new base number using just the base numbers, and the new exponent using just the exponents (at least for the most part).

8. DDCamp

|dw:1433815197986:dw|

9. jewelotaku2001

So, going off of that, would the answer be:$10.62 \times 10^15$

10. jewelotaku2001

That's supposed to be 15...

11. DDCamp

Almost, but I think you multiplied instead of dividing.

12. jewelotaku2001

I'm confused...

13. DDCamp

$3.54 / 3.00 →1.18 \\ 10^7 / 10^8 → 10^{-1}$

14. jewelotaku2001

So would the answer be:$1.18 \times 10^-1$

15. DDCamp

Yup!

16. jewelotaku2001

Ok thank you! :-)

17. DDCamp

Also, if you want exponents to have multiple characters (like 10^15 or 10^-1), you can type it like this: 10^{15} 10^{-1} 10^{anything you want inside the brackets!} and get this: $10^{15} \\ 10^{-1} \\10^{anything you want inside the brackets!}$

18. jewelotaku2001

Woah 0-0