A radio signal travels at 3.00 times 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the Earth's surface if the satellite is orbiting at a height of 3.54 times 10^7 meters? Please help me with this. I'm not good at Scientific Notation...

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A radio signal travels at 3.00 times 10^8 meters per second. How many seconds will it take for a radio signal to travel from a satellite to the Earth's surface if the satellite is orbiting at a height of 3.54 times 10^7 meters? Please help me with this. I'm not good at Scientific Notation...

Mathematics
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The following are the equations written:
\[3.00 \times 10^8\] \[3.54 \times 10^7\]
To find the time elapsed, you can use the equation: \[time = distance / speed\]

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So, would that be 1.15 seconds?
Working with scientific notation can be tricky at first, but it does make things easier in the long run. Each number in scientific notation has two parts, the base number and the part with the exponent, and you have to make sure you use the entire number in your calculations.
The first notation is 30,000,000 and the second one is 35,400,000. I've already calculated what they were.
The nice part is this: You can find the new base number using just the base numbers, and the new exponent using just the exponents (at least for the most part).
|dw:1433815197986:dw|
So, going off of that, would the answer be:\[10.62 \times 10^15\]
That's supposed to be 15...
Almost, but I think you multiplied instead of dividing.
I'm confused...
\[3.54 / 3.00 →1.18 \\ 10^7 / 10^8 → 10^{-1}\]
So would the answer be:\[1.18 \times 10^-1\]
Yup!
Ok thank you! :-)
Also, if you want exponents to have multiple characters (like 10^15 or 10^-1), you can type it like this: 10^{15} 10^{-1} 10^{anything you want inside the brackets!} and get this: \[10^{15} \\ 10^{-1} \\10^{anything you want inside the brackets!}\]
Woah 0-0

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