anonymous
  • anonymous
FAN AND MEDAL Can someone please work through this with me?? A restaurant has x floors. The number of tables on each floor is 4 less than the number of floors. The number of chairs with each table is 1 less than the number of tables on each floor. The expression below shows the total number of chairs in the restaurant: x(x - 4)(x - 5) Part A: What type of polynomial is x(x - 4)(x - 5)? (3 points) Part B: What is the degree of the polynomial x(x - 4)? (3 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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anonymous
  • anonymous
@peachpi
anonymous
  • anonymous
the highest exponent tells the degree. 2nd degree → x² → quadratic 3rd degree → x³ → cubic
anonymous
  • anonymous
I know that but how don't I figure that out because x(x - 4)(x - 5) is already factored..

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anonymous
  • anonymous
When you multiply them together, what will the highest exponent be?
anonymous
  • anonymous
\[x ^{2}\]
anonymous
  • anonymous
No. You have 3 different factors, all of which include an x. If you can't tell by looking, you may need to multiply them out.
anonymous
  • anonymous
Oh okay hang on a sec.
anonymous
  • anonymous
x^3
anonymous
  • anonymous
right
anonymous
  • anonymous
so then what type of polynomial is it?
anonymous
  • anonymous
I got \[x ^{3}-9x+20\] so it would be a third degree trinomial right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Okay thank you so much for your help!!
anonymous
  • anonymous
you're welcome

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