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Zenmo
 one year ago
Find the angle between the forces given the magnitude of their resultant. (Hint: Write force 1 as a vector in the direction of the positive xaxis and force 2 as a vector at an angle theta with the positive xaxis.
Force 1=45 pounds, Force 2=60 pounds, Resultant Force= 90 pounds.
Zenmo
 one year ago
Find the angle between the forces given the magnitude of their resultant. (Hint: Write force 1 as a vector in the direction of the positive xaxis and force 2 as a vector at an angle theta with the positive xaxis. Force 1=45 pounds, Force 2=60 pounds, Resultant Force= 90 pounds.

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perl
 one year ago
Best ResponseYou've already chosen the best response.1Did you attempt to make a force diagram?

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1Well, that is what I have so far.

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1This involves the section of "Vectors in a plane."

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1Ops, forgot to put a 60 in there. Now, I'm not sure what to do next.

perl
 one year ago
Best ResponseYou've already chosen the best response.1The directions state that the magnitude of the resultant is 90 pounds.

perl
 one year ago
Best ResponseYou've already chosen the best response.1If we call the resultant vector R then magnitude of R= sqrt( Rx^2 + Ry^2)

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1What is the magnitude of R= sqrt(Rx^2+Ry^2) formula/name called?

perl
 one year ago
Best ResponseYou've already chosen the best response.1that comes from pythagorean theorem

perl
 one year ago
Best ResponseYou've already chosen the best response.1the length of a vector is the length of the hypotenuse

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1Just to check, R= sqrt (Rx^2+Ry^2) is the same as C= sqrt (Ax^2+By^2) ?

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1=\[2025+3600\cos^2t+5400cost+3600\sin^2=8100\]

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1is that the correct next step?

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1ops forgot to put the t for 3600sin^2t.

perl
 one year ago
Best ResponseYou've already chosen the best response.1we can simplify this by factoring out 3600 from sin^2 t and cos^2 t

perl
 one year ago
Best ResponseYou've already chosen the best response.1$$\large {2025+3600\cos^2t+5400\cos t+3600\sin^2 t=8100 \\ 2025+3600( \cos^2t +\sin^2 t ) +5400\cos t=8100 \\2025+3600( 1) +5400\cos t=8100 } $$

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1\[5625+5400\cos t = 8100. >5400\cos t =2475. >\cos t =2475/5400. > \cos t = .4583 > arc \cos t = 62.7 degrees.\]

perl
 one year ago
Best ResponseYou've already chosen the best response.1now solve for t, the angle

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1\[\cos t = 0.4583 > \arccos t (0.4583)\]

Zenmo
 one year ago
Best ResponseYou've already chosen the best response.1Ok, that is the answer. Thanks! One small question, so dealing with these type of problems, this will always involve the Pythagorean Theorem of R=sqrt(Rx^2+Ry^2)?

perl
 one year ago
Best ResponseYou've already chosen the best response.1if you need to find magnitude of a vector, then yes :)
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