anonymous
  • anonymous
How do you factor 5c^3+2c^2-5cd^2-2d^2????? 😔😔😔😔😔😔
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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perl
  • perl
did you try grouping
anonymous
  • anonymous
No I haven't
pooja195
  • pooja195
I dont think this is something that can be factored :/

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pooja195
  • pooja195
\[\huge~5c^3−5cd^2+2c^2−2d^2 \] tthis is all you would get just organized .-.
pooja195
  • pooja195
no like terms either :/
anonymous
  • anonymous
Thx u
pooja195
  • pooja195
id if i helped :/
anonymous
  • anonymous
Now I'm stuck lol
perl
  • perl
This does factor. \[\Large { 5c^3+2c^2-5cd^2-2d^2 \\= c^2 (5c + 2) - d^2( 5c + 2) \\ = (5c+2)( c^2 - d^2) \\ = (5c+2)( c -d )( c + d) }\]
pooja195
  • pooja195
5cd^2??
perl
  • perl
you can also factor that way if you like
perl
  • perl
\[\huge{5c^3−5cd^2+2c^2−2d^2 \\ =5c ~(c^2 - d^2) + 2( c^2 - d^2) \\ = (c^2 - d^2) ( 5c+2) \\= (c-d)(c+d)(5c+2) } \]
pooja195
  • pooja195
good job perl :)
anonymous
  • anonymous
Thx u
perl
  • perl
Thanks :)

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